a) x ⋮ 12, x ⋮ 25, x ⋮ 30 và 0 < x ≤ 500.
b) x ⋮ 12, x ⋮ 21, x ⋮ 28 và 150 < x < 300.
c) x ⋮ 15, x ⋮ 12, x ⋮ 18 và 0 < x < 300.
d) x ⋮ 6, x ⋮ 8, x ⋮ 12 và x ≠ 0 nhỏ nhất.
e) x ⋮ 10, x ⋮ 12, x ⋮ 60 và 120 ≤ x < 200.
f) (x + 10) ⋮ 5, (x - 18) ⋮ 6, (x + 21) ⋮ 7 và 500 < x < 700.
g) x : 5 (dư 3), x : 6 (dư 4) và x < 59
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a) \(x+5=20-\left(12-7\right)\)
\(\Rightarrow x+5=20-5\)
\(\Rightarrow x+5=15\)
\(\Rightarrow x=15-5\)
\(\Rightarrow x=10\)
b) \(15-\left(3+2x\right)=2^2\)
\(\Rightarrow3+2x=15-4\)
\(\Rightarrow3+2x=11\)
\(\Rightarrow2x=11-3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=\dfrac{8}{2}\)
\(\Rightarrow x=4\)
c) \(-11-\left(19-x\right)=50\)
\(\Rightarrow19-x=-11-50\)
\(\Rightarrow19-x=-61\)
\(\Rightarrow x=61+19\)
\(\Rightarrow x=80\)
d) \(159-\left(25-x\right)=43\)
\(\Rightarrow25-x=159-43\)
\(\Rightarrow25-x=116\)
\(\Rightarrow x=25-116\)
\(\Rightarrow x=-91\)
e) \(\left(79-x\right)-43=-\left(17-52\right)\)
\(\Rightarrow\left(79-x\right)-43=52-17\)
\(\Rightarrow79-x-43=35\)
\(\Rightarrow36-x=35\)
\(\Rightarrow x=1\)
f) \(\left(7+x\right)-\left(21-13\right)=32\)
\(\Rightarrow7+x-8=32\)
\(\Rightarrow x-1=32\)
\(\Rightarrow x=32+1\)
\(\Rightarrow x=33\)
g) \(-x+20=-15+8+13\)
\(\Rightarrow-x+20=6\)
\(\Rightarrow x=20-6\)
\(\Rightarrow x=14\)
h) \(-\left(-x+13-142\right)+18=55\)
\(\Rightarrow x-13+142+18=55\)
\(\Rightarrow x+147=55\)
\(\Rightarrow x=55-147\)
\(\Rightarrow x=-92\)
\(17\cdot85+15\cdot17-120\)
\(=17\cdot\left(85+15\right)-120\)
\(=17\cdot100-120\)
\(=1700-120\)
\(=1580\)
\(\left(2+4+6+...+2n\right)-53=103\)
\(\Rightarrow\left[\left(2n-2\right):2+1\right]\cdot\left(2n+2\right):2-53=103\)
\(\Rightarrow\left[2\left(n-1\right):2+1\right]\cdot\left(2n+2\right):2=103+53\)
\(\Rightarrow\left(n-1+1\right)\cdot2\cdot\left(n+1\right):2=156\)
\(\Rightarrow n\cdot\left(n+1\right)=156\)
\(\Rightarrow n\cdot\left(n+1\right)=12\cdot13\)
\(\Rightarrow n=12\)
Vậy: n = 12
\(A=1+3+3^2+...+3^{2021}\\3\cdot A=3\cdot(1+3+3^2+...+3^{2021})\\3\cdot A=3+3^2+3^3+...+3^{2022}\\3A-A=(3+3^2+3^3+...+3^{2022})-(1+3+3^2+...+3^{2021})\\2A=3+3^2+3^3+...+3^{2022}-1-3-3^2-...-3^{2021}\\2A=3^{2022}-1\\\Rightarrow A=\dfrac{3^{2022}-1}{2}\)
`#3107.101107`
\(A=1+3+3^2+...+3^{2021}\)
\(3A=3+3^2+3^3+...+3^{2021}\)
\(3A-A=\left(3+3^2+3^3+...+3^{2021}\right)-\left(1+3+3^2+...+3^{2021}\right)\)
\(2A=3+3^2+3^3+...+3^{2021}-1-3-3^2-...-3^{2021}\)
\(2A=3^{2021}-1\)
\(A=\dfrac{3^{2021}-1}{2}\)
Vậy, \(A=\dfrac{3^{2021}-1}{2}.\)
x + 5 chia hết cho x + 3
⇒ x + 3 + 2 chia hết cho x + 3
⇒ x + 3 chia hết cho x + 3 và 2 chia hết cho x + 3
⇒ x + 3 ∈ Ư(2)
Mà: Ư(2) = {1; -1; 2; -2}
⇒ x + 3 ∈ {1; -1; 2; -2}
⇒ x ∈ {-2; -4; -1; -5}
\(6\cdot x-5=19\)
\(\Rightarrow6\cdot x=19+5\)
\(\Rightarrow6\cdot x=24\)
\(\Rightarrow x=\dfrac{24}{6}\)
\(\Rightarrow x=4\)
Vậy: x = 4