\(\dfrac{3}{8}+\left(x-\dfrac{5}{24}\right):\dfrac{2}{3}=1\)

=>\(\left(x-\dfrac{5}{24}\right):\dfrac{2}{3}=1-\dfrac{3}{8}=\dfrac{5}{8}\)

=>\(x-\dfrac{5}{24}=\dfrac{5}{8}\times\dfrac{2}{3}=\dfrac{10}{24}\)

=>\(x=\dfrac{10}{24}+\dfrac{5}{24}=\dfrac{15}{24}=\dfrac{5}{8}\)

\(\dfrac{3}{8}+\left(x-\dfrac{5}{24}\right):\dfrac{2}{3}=1\)

\(=>\left(x-\dfrac{5}{24}\right):\dfrac{2}{3}=1-\dfrac{3}{8}=\dfrac{8}{8}-\dfrac{3}{8}\)

\(=>\left(x-\dfrac{5}{24}\right):\dfrac{2}{3}=\dfrac{5}{8}\)

\(=>x-\dfrac{5}{24}=\dfrac{5}{8}\times\dfrac{2}{3}\)

\(=>x-\dfrac{5}{24}=\dfrac{5}{12}\)

\(=>x=\dfrac{5}{12}+\dfrac{5}{24}=\dfrac{10}{24}+\dfrac{5}{24}\)

\(=>x=\dfrac{15}{24}=\dfrac{5}{8}\)

\(#NqHahh\)

(125 + x) : x = 6

=> 125 + x = 6 × x

=> 6 × x - x = 125

=> 5 × x = 125

=> x = 125 : 5

=> x = 25

\(\dfrac{125+x}{x}=6\)(ĐKXĐ: \(x\ne0\))

=>6x=x+125

=>5x=125

=>x=25(nhận)

Trong 500 g nước biển có số muối là :

     500 x 4% = 20 g

Để tỉ lệ muối trong dung dịch là 2% thì cần số gam nước là:

     20 : 2% = 1000 ( g )

Cần đổ thêm số nước tinh khiết là :

     1000 - 500 = 500 g = 500 ml

             Đáp số : 500 ml nước

Đổi: `1dm=10cm`

Thể tích của hộp quà đó bằng:

`15\times10\times12=1800(cm^3)`

câu a

\(\dfrac{9}{5}\cdot y-\dfrac{3}{5}\cdot\left(y+5\right)=33\\ \dfrac{9}{5}\cdot y-\dfrac{3}{5}\cdot y-3=33\\ \dfrac{6}{5}y-3=33\\ \dfrac{6}{5}y=36\\ y=30\)

câu b

\(75\%\cdot y+y+0,5\cdot y+y:4=25\\ y\cdot\left(75\%+1+0,5\right)+y:4=25\\ y\cdot2,25+y:4=25\\ 9\cdot y+y=100\\ 10y=100\\ y=10\)

x= ........................................................................................................ké

a: 0,9x7+1,8x45+0,9+1,8

=0,9x7+0,9x90+0,9x3

=0,9x(7+90+3)=0,9x100=90

b: 20,24x5,8-20,24x4,7-12,24-8

=20,24x1,1-20,24

=20,24x0,1=2,024

a)                      

\(0,9\times7+1,8\times45+0,9+1,8\) 

\(=0,9\times\left(7+1\right)+1,8\times\left(45+1\right)\)

\(=0,9\times8+0,9\times2\times46\)

\(=0,9\times8+0,9\times92\)

\(=0,9\times\left(8+92\right)\)

\(=0,9\times100\)

\(=90\)

b) \(20,24\times5,8-20,24\times4,7-12,24-8\) 

\(=20,24\times\left(5,8-4,7\right)-\left(12,24+8\right)\)

\(=20,24\times1,1-20,24\)

\(=20,24\times\left(1,1-1\right)\)

\(=20,24\times0,1\) 

\(=2,024\)

nhờ mọi người giải giúp em với ạ,em đang cần gấp

\(12,8\times\dfrac{1}{2}+12,8\times0,25+12,8\times\dfrac{1}{4}\)

\(=12,8\times0,5+12,8\times0,25+12,8\times0,25\)

\(=12,8\times\left(0,5+0,25+0,25\right)\)

\(=12,8\times1\)

\(=12,8\)

\(12,8\times\dfrac{1}{2}+12,8\times0,25+12,8\times\dfrac{1}{4}\\ =12,8\times\dfrac{1}{2}+12,8\times\dfrac{25}{100}+12,8\times\dfrac{1}{4}\\ =12,8\times\dfrac{1}{2}+12,8\times\dfrac{1}{4}+12,8\times\dfrac{1}{4}\\ =12,8\times\left(\dfrac{2}{4}+\dfrac{1}{4}+\dfrac{1}{4}\right)\\ =12,8\times\dfrac{4}{4}=12,8\times1=12,8\)

Sửa đề : \(\dfrac{2025\times2024-1}{2023\times2025+2024}\)

\(=\)\(\dfrac{2025\times\left(2023+1\right)-1}{2023\times2025+2024}\)

\(=\dfrac{2025\times2023+2025-1}{2023\times2025+2024}\)

\(=\dfrac{2025\times2023+\left(2025-1\right)}{2023\times2025+2024}\)

\(=\dfrac{2025\times2023+2024}{2023\times2025+2024}\)

\(=1\)

@\(\text{格雷斯}\)