Ta có:\(18:x\)

\(\Rightarrow x\in\left\{1;2;3;6;9;18\right\}\)

Vì \(x>6\)

\(\Rightarrow x=9;18\)

Đưa đã rồi làm kkk

\(\left(80x-801\right).12=0\)

\(80x-801=0:12\)

\(80x-801=0\)

\(80x=0+801\)

\(80x=801\Rightarrow x=\dfrac{801}{80}\)

This is Nam's ball

╰‿╯𝕸𝖀亗

chúc may mắn lần sau!

\(45\left(\dfrac{-3}{5}-\dfrac{8}{15}+\dfrac{7}{3}-\dfrac{5}{9}\right)\)

\(=45\left(\dfrac{-9}{15}-\dfrac{8}{15}+\dfrac{21}{9}-\dfrac{5}{9}\right)\)

\(=45\left(-\dfrac{17}{15}+\dfrac{16}{9}\right)\)

\(=45\times\dfrac{29}{45}=29\)

\(285\times y+y\times\)\(115=800\)

\(y\times\left(285+115\right)=800\)

\(y\times400=800\)

\(y=800:400\Rightarrow y=2\)

\(-\dfrac{1}{200}\)và\(-\dfrac{1}{100}\)

Ta có :\(-\dfrac{1}{100}=-\dfrac{2}{100}\)

   Vì \(-\dfrac{1}{200}>-\dfrac{2}{200}\) nên \(-\dfrac{1}{200}>-\dfrac{1}{100}\)