Nguyễn Duy Vũ
Giới thiệu về bản thân
ta co d//Δ : x+4y-2=0 => phuong trinh d co dang x+4y+c=0
mat khac:d(A,d) =3 => -2+4.3+c/\(\sqrt{1+16}\) =3 => 10+c =3\(\sqrt{17}\)
[c=3\(\sqrt{17}\)-10 ==>[d1: x+4y+3\(\sqrt{17}\)-10=0
[c=-3\(\sqrt{17}\)-10 [d2:x+4y-3\(\sqrt{17}\)-10=0
vay 2 duong thang thoa man : x+4y+3\(\sqrt{17}\) -10 =0: x+4y-3\(\sqrt{17}\)-10=0
C(xc;yc)
ta co OC=(xc;yc),AB=(-2;5) ==>-3AB = (6;-15)
OC-3AB <=> xc=6 ; yc=-15
D doi xung A qua C hay C la trung diem AD <=> {xc= xa+xd/2
{yc=ya+yd/2
<=> xd=2xc-xa=2.6-3=9
<=>yd-ya=2=(-15) - (-5) =-25
==> D(9;-25)
tim dkxd
{2x^2 +5≥0 ∀x∈ R
{ x^2-x+11≥0 ∀x∈12 ==> x∈R
<=>2x^2+5 =x^2-x+11
<=>x^2+x-6=0 (=) x^2-2x+3x-6=0
<=> x(x-2)+3(x-2)=0 (=) (x+3)(x-2)=0 <=>{x=-3
{x=2
gia ban x san pham la 170x nghin dong
de nha san xuat k bi lo :
P(x) ≤ 170x
<>x2+30x+3300≤ 170x
<>x2-140x+3300≤0
<>(x-110)(x-30)
ta lap bang xet dau
x -∞ 30 110 +∞
f(x) + 0 - 0 +
vay fx ≤0 <=> x∈ [30,100] do Do de nha san xuat k bi lo thi so sp dc san xuat trong doan [30,100]