\(4,32\times1,5+43,2\times0,47+\dfrac{432}{100}\times2,8\)

\(=4,32\times1,5+4,32\times4,7+4,32\times2,8\)

\(=4,32\times\left(1,5+4,7+2,8\right)\)

\(=4,32\times9=38,88\)

`@`Phan Trung Khánh Không được cop Chat GPT nhé!

`-3752 - (29 - 3632) -51`

`= -3752 - 29 + 3632 - 51`

`= (-3752 + 3632) - (29 + 51)`

`= -120 - 80`

`=-200`

Chúc mừg số 1 vs số 4 của danh sách `HTGD` nhe <33

vs cả số `6` vs số `9` trong danh sách nhận giải nhe <3

\(12\%\) của \(150\) là số :

\(\dfrac{12}{100}.150=18\)

Đáp số : `18`

\(b,\sqrt{196}-\sqrt{64}+\sqrt{9}\)

\(=14-8+3\)

\(=6+3\)

\(=9\)

`---`

\(d,\sqrt{289}-\sqrt{144}+\sqrt{\left(-3\right)^2}\)

\(=17-12+\sqrt{9}\)

\(=17-12+3\)

\(=5+3\)

`=8`

\(f,\sqrt{1\dfrac{24}{25}}:1,2-2023^0+\left(-\dfrac{1}{3}\right)^2.\sqrt{\left(-3\right)^2}\)

\(=\sqrt{\dfrac{49}{25}}:\dfrac{6}{5}-1+\dfrac{1}{9}.\sqrt{9}\)

\(=\dfrac{7}{5}:\dfrac{6}{5}-1+\dfrac{1}{9}.3\)

\(=\dfrac{7}{6}-1+\dfrac{1}{3}\)

\(=\dfrac{1}{6}+\dfrac{1}{3}\)

\(=\dfrac{1}{2}\)

${color{#B0E0E6}}{\text{Working}}$

P/S: Nếu ai thấy tớ sai ở đâu thì bảo tớ ạ!

\(a,-\dfrac{3}{4}x-\dfrac{1}{2}=\dfrac{1}{6}\)

\(\Rightarrow-\dfrac{3}{4}x=\dfrac{1}{6}+\dfrac{1}{2}\)

\(\Rightarrow-\dfrac{3}{4}x=\dfrac{2}{3}\)

\(\Rightarrow x=\dfrac{2}{3}:-\dfrac{3}{4}\)

\(\Rightarrow x=-\dfrac{8}{9}\)

Vậy \(x=-\dfrac{8}{9}\)

\(b,\left|x\right|-2,96=\left(-0,2\right)^2\)

\(\Rightarrow\left|x\right|-2,96=0,04\)

\(\Rightarrow\left|x\right|=0,04+2,96\)

\(\Rightarrow\left|x\right|=3\)

\(\Rightarrow x=3\) hoặc \(x=-3\)

Vậy...

\(c,\left|2x-\dfrac{1}{5}\right|=0\)

\(\Rightarrow2x-\dfrac{1}{5}=0\)

\(\Rightarrow2x=0+\dfrac{1}{5}\)

\(\Rightarrow2x=\dfrac{1}{5}\)

\(\Rightarrow x=\dfrac{1}{5}:2\)

\(\Rightarrow x=\dfrac{1}{10}\)

\(d,\)\(\left|x+\dfrac{5}{2}\right|-\dfrac{2}{3}=\left(\dfrac{-1}{2}\right)^3:\left(\dfrac{-1}{2}\right)^2\)

\(\Rightarrow\left|x+\dfrac{5}{2}\right|-\dfrac{2}{3}=-\dfrac{1}{2}\)

\(\Rightarrow\left|x+\dfrac{5}{2}\right|=-\dfrac{1}{2}+\dfrac{2}{3}\)

\(\Rightarrow\left|x+\dfrac{5}{2}\right|=\dfrac{1}{6}\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{5}{2}=\dfrac{1}{6}\\x+\dfrac{5}{2}=-\dfrac{1}{6}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{6}-\dfrac{5}{2}\\x=-\dfrac{1}{6}-\dfrac{5}{2}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{3}\\x=-\dfrac{8}{3}\end{matrix}\right.\)

Vậy \(x\in\left\{-\dfrac{7}{3};-\dfrac{8}{3}\right\}\)

P/S : Nếu tớ sai ở đâu thì mọi người góp ý giúp ạ!

\(-------\)

\(\dfrac{25}{100}\times30+2,5:10+\dfrac{1}{4}\times29+0,25\times40\)

\(=0,25\times30+0,25\times1+0,25\times29+0,25\times40\)

\(=0,25\times\left(30+1+29+40\right)\)

\(=0,25\times100\)

\(=25\)

\(3,27\times0,25+2,3\times\dfrac{1}{4}+1,75:4+2,68\times25\%\)

\(=3,27\times0,25+2,3\times0,25+1,75\times0,25+2,68\times0,25\)

\(=\left(3,27+2,3+1,75+2,68\right)\times0,25\)

\(=\left(5,57+1,75+2,68\right)\times0,25\)

\(=\left(7,32+2,68\right)\times0,25\)

\(=10\times0,25\)

\(=2,5\)

\(\dfrac{154,8+42,7}{x}+35=74,5\)

\(\Rightarrow\dfrac{197,5}{x}+35=74,5\)

\(\Rightarrow\)\(\dfrac{197,5}{x}=74,5-35\)

\(\Rightarrow\dfrac{197,5}{x}=39,5\)

\(\Rightarrow x=197,5:39,5\)

\(\Rightarrow x=5\)