Bài 1: Tìm x:
a,\(\left(x-2013\right)^{2014}=1\)
Bài 2: So sánh:
a, \(2^{333}\) và \(3^{222}\)
b, \(3^{2009}\)và \(9^{1005}\)
c, \(99^{20}\) và \(9999^{10}\)
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1. The roads in VN are too narrow for us to travel easily.
2. It's very important to obey traffic rules when using the road.
3. Two days ago we got stuck in the traffic jam for over two hours.
4. Most streets in the city centre are congested during rush hours.
1. There is a good.............................of meat on the stall
A. kind B. selection C. type D. stall
2. ....................he..................last semester?-Very well.
A. How/ studied B. How did / studied C. How does / study D. How did /study
3. An speaks....................................
A. English perfect B. English perfectly C. perfectly English D. perfected English
4. The dentist......................a cavity in Nam's tooth last Sunday.
A. pulled B. drilled C. Washed D. filled
5. Liz never goes to school late and I.....................
A. didn't either B. don't too C. neither do D. don't either
Choose the best answer (A, B, C or D) for each sentence below
1. There is a good.............................of meat on the stall
A. kind B. selection C. type D. stall
2. ....................he..................last semester?-Very well.
A. How/ studied B. How did / studied C. How does / study D. How did /study
3. An speaks....................................
A. English perfect B. English perfectly C. perfectly English D. perfected English
4. The dentist......................a cavity in Nam's tooth last Sunday.
A. pulled B. drilled C. Washed D. filled
5. Liz never goes to school late and I.....................
A. didn't either B. don't too C. neither do D. don't either
Vì \(\Delta ABC\) vuông tại A \(\Rightarrow\widehat{A}=90^0\Leftrightarrow BC^2=AB^2+AC^2\) ( ĐL Pytago )
Vì \(\frac{AB}{AC}=\frac{8}{15}\Leftrightarrow\frac{AB}{8}=\frac{AC}{15}\Leftrightarrow\frac{AB^2}{8^2}=\frac{AC^2}{15^2}\). Áp dụng t/c dãy tỉ số bằng nhau
Ta có : \(\frac{AB^2}{8^2}=\frac{AC^2}{15^2}=\frac{AB^2+AC^2}{8^2+15^2}=\frac{BC^2}{64+225}=\frac{2061}{289}=9\)
\(\frac{AB^2}{8^2}=9\Leftrightarrow\sqrt{\frac{AB^2}{8^2}}=\sqrt{9}\Leftrightarrow\frac{AB}{8}=3\Leftrightarrow AB=3.8=24\left(cm\right)\)
\(\frac{AC^2}{15^2}=9\Leftrightarrow\sqrt{\frac{AC^2}{15^2}}=\sqrt{9}\Leftrightarrow\frac{AC}{15}=3\Leftrightarrow AC=15.3=45\left(cm\right)\)
Chu vi \(\Delta ABC=24+45+51=120\left(cm\right)\)
Diện tích \(\Delta ABC=\frac{a\times h}{2}=\frac{24\times45}{2}=\frac{1080}{2}=540\left(cm\right)\)
Bài 1:
\(\left(x-2013\right)^{2014}=1\)
\(\Leftrightarrow\orbr{\begin{cases}x-2013=1\\x-2013=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2014\\x=2012\end{cases}}}\)
Vậy x=2014; x=2012
Bài 2:
a) Ta có: \(2^{333}=\left(2^3\right)^{111}=8^{111}\)
\(3^{222}=\left(3^2\right)^{111}=9^{111}\)
Ta thấy 8<9 => \(8^{111}< 9^{111}\Rightarrow2^{333}< 3^{222}\)
b) Ta có: \(9^{1005}=\left(3^2\right)^{1005}=3^{2010}\)
Ta thấy \(3^{2009}< 3^{2010}\Rightarrow3^{2009}< 9^{1005}\)
c) \(99^{20}=\left(99^2\right)^{10}=9801^{10}\)
Thấy \(9801< 9999\Rightarrow9801^{10}< 9999^{10}\Rightarrow99^2< 9999^{10}\)
B1: (x-2013)2014=1 =>x-2013=1;-1=>x=2014;2012 B2: a)có:2333=(23)111=8111 ; 3222=(32)111=9111 =>2333<3222(8111<9111) b)có:91005=(32)1005=32010 >32009 =>91005>32009 c)có:9920=(992)10=980110<999910 =>9920<999910