Tìm x biết x + 1/4 = 7/2
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a: \(\dfrac{3}{4}=\dfrac{3\cdot4}{4\cdot4}=\dfrac{12}{16};\dfrac{1}{2}=\dfrac{1\cdot8}{2\cdot8}=\dfrac{8}{16};\dfrac{7}{8}=\dfrac{7\cdot2}{8\cdot2}=\dfrac{14}{16}\)
mà 8<12<14<15
nên \(\dfrac{1}{2}< \dfrac{3}{4}< \dfrac{7}{8}< \dfrac{15}{16}\)
b: 20/2=10; 21/20=1,05; 45/40=1,125; 27/20=1,35
mà 10>1,35>1,125>1,05
nên \(\dfrac{20}{2}>\dfrac{27}{20}>\dfrac{45}{40}>\dfrac{21}{20}\)
\(\dfrac{3}{5}=\dfrac{3\cdot3}{5\cdot3}=\dfrac{9}{15}\)
\(\dfrac{13}{15}=\dfrac{13\cdot1}{15\cdot1}=\dfrac{13}{15}\)
mà 9<13
nên \(\dfrac{3}{5}< \dfrac{13}{15}\)
\(\dfrac{3}{10}=\dfrac{3\cdot1}{10\cdot1}=\dfrac{3}{10};\dfrac{2}{5}=\dfrac{2\cdot2}{5\cdot2}=\dfrac{4}{10}\)
mà 3<10
nên \(\dfrac{3}{10}< \dfrac{2}{5}\)
Vì 19<17
nên \(\dfrac{13}{19}>\dfrac{13}{17}\)
\(\dfrac{3}{5}>\dfrac{13}{15}\\ \dfrac{3}{10}< \dfrac{2}{5}\\ \dfrac{13}{19}< \dfrac{13}{17}.\)
M=1x2+2x3+3x4+xxx+19x20
3M=1x2x3+2x3x3+3x4x3+xxx+19x20x3
3M=1x2x(3-0)+2x3x(4-1)+3x4x(5-2)+xxx+19x20x(21-18)
3M=(1x2x3-0x1x2)+(2x3x4-1x2x3)+(3x4x5-2x3x4)+xxx+(19x20x21-18x19x20)
3M=19x20x21-0x1x2
3M=7980-0
3M=7980
M=7980:3
M=2660
Vậy M=2660
Chúc bạn học tốt nha!!!!! ^^
\(A=1\cdot2+2\cdot3+...+19\cdot20\)
\(=1\left(1+1\right)+2\left(2+1\right)+...+19\left(19+1\right)\)
\(=\left(1^2+2^2+...+19^2\right)+\left(1+2+...+19\right)\)
\(=\dfrac{19\left(19+1\right)\left(2\cdot19+1\right)}{6}+\dfrac{19\cdot20}{2}\)
\(=2470+190=2660\)
Ta có:
\(\dfrac{24}{24}=24:24=1\)
\(\dfrac{26}{26}=26:26=1\)
\(\dfrac{1122}{1122}=1122:1122=1\)
\(\dfrac{25}{25}=25:25=1\)
\(\dfrac{27}{27}=27:27=1\)
Vậy nên ta có \(\dfrac{24}{24}=1;\dfrac{26}{26}=1;\dfrac{1122}{1122}=1;\dfrac{25}{25}=1;\dfrac{27}{27}=1\)
\(x+\dfrac{1}{4}=\dfrac{7}{2}\)
\(x=\dfrac{7}{2}-\dfrac{1}{4}\)
\(x=\dfrac{14}{4}-\dfrac{1}{4}\)
\(x=\dfrac{13}{4}\)
\(x\) + \(\dfrac{1}{4}\) = \(\dfrac{7}{2}\)
\(x\) = \(\dfrac{7}{2}\) - \(\dfrac{1}{4}\)
\(x\) = \(\dfrac{13}{4}\)