Một lò xo dài thêm 10cm khi treo vào đấu của nó một vật có trọng lượng 20 N . tiếp tục treo thêm một vật có trọng lượng 15N nữa thì lò xo dài bao nhiêu ? Biết chiều dài tự nhiên cx lò xo này là 20cm. Giúp e vs ạ
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\(\dfrac{2}{3}-\left(-\dfrac{5}{7}+\dfrac{2}{3}\right)=\dfrac{2}{3}+\dfrac{5}{7}-\dfrac{2}{3}=\dfrac{5}{7}\)
\(\dfrac{14}{13}+\left(\dfrac{-1}{13}-\dfrac{19}{20}\right)=\dfrac{14}{13}-\dfrac{1}{13}-\dfrac{19}{20}\)
\(=\dfrac{13}{13}-\dfrac{19}{20}=1-\dfrac{19}{20}=\dfrac{20}{20}-\dfrac{19}{20}\)
\(=\dfrac{1}{20}\)
=\(\dfrac{14}{13}\) + ( \(\dfrac{-20}{260}\) - \(\dfrac{247}{260}\) )
=\(\dfrac{14}{13}\) + \(\dfrac{-267}{260}\)
=\(\dfrac{280}{260}\) + \(\dfrac{-267}{260}\)
=\(\dfrac{13}{260}\)
=\(\dfrac{1}{20}\)
\(\dfrac{-13}{15}+\dfrac{5}{21}-\dfrac{1}{3}-\dfrac{2}{15}+\dfrac{2}{21}\)
\(=\left(\dfrac{-13}{15}-\dfrac{2}{15}\right)+\left(\dfrac{5}{21}+\dfrac{2}{21}-\dfrac{1}{3}\right)\)
\(=\dfrac{-15}{15}+\left(\dfrac{7}{21}-\dfrac{1}{3}\right)\)
\(=-1+\left(\dfrac{1}{3}-\dfrac{1}{3}\right)\)
\(=-1+0=-1\)
\(\dfrac{-13}{15}\) + \(\dfrac{5}{21}\) - \(\dfrac{1}{3}\) - \(\dfrac{2}{15}\) + \(\dfrac{2}{21}\)
=\(\dfrac{-13}{15}\) + \(\dfrac{2}{15}\) - \(\dfrac{5}{21}\) + \(\dfrac{2}{21}\) - \(\dfrac{1}{3}\)
= \(\dfrac{-15}{15}\) + \(\dfrac{7}{21}\) - \(\dfrac{1}{3}\)
= \(\dfrac{-3}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)
= \(\dfrac{-2}{3}\) - \(\dfrac{1}{3}\)
= \(\dfrac{-3}{3}\)
= -1
\(\dfrac{7}{4}.\dfrac{29}{5}-\dfrac{7}{5}.\dfrac{29}{4}+1\dfrac{1}{2}\)
\(=\dfrac{7}{5}.\dfrac{29}{4}-\dfrac{7}{5}.\dfrac{29}{4}+1\dfrac{1}{2}\)
\(=0+1\dfrac{1}{2}=1\dfrac{1}{2}=\dfrac{3}{2}\)
\(\dfrac{8}{21}-\dfrac{5}{11}-\left(-\dfrac{13}{21}\right)-\dfrac{6}{11}\)
\(=\dfrac{8}{21}-\dfrac{5}{11}+\dfrac{13}{21}-\dfrac{6}{11}\)
\(=\left(\dfrac{8}{21}+\dfrac{13}{21}\right)+\left(-\dfrac{5}{11}-\dfrac{6}{11}\right)\)
\(=1+\left(-1\right)=0\)
\(\dfrac{8}{21}-\dfrac{5}{11}-\left(-\dfrac{13}{21}\right)-\dfrac{6}{11}\)
\(=\dfrac{8}{21}-\dfrac{5}{11}+\dfrac{13}{21}-\dfrac{6}{11}\)
\(=\left(\dfrac{8}{21}+\dfrac{13}{21}\right)+\left(-\dfrac{5}{11}-\dfrac{6}{11}\right)\)
\(=\dfrac{21}{21}-\dfrac{11}{11}\)
\(=1-1=0\)