15𝑥+83=(4𝑥−5)−(2𝑥+3)

15𝑥+83=(4𝑥−5)−(2𝑥+3)

15𝑥+83=(4𝑥−5)−2𝑥−3

𝑥= -7

chúc bn hok tốt !!!!!!

\(\left(x+2\right)\left(x-3\right)< 0\)

Vì x + 2 > x - 3

nên \(\hept{\begin{cases}x+2>0\\x-3< 0\end{cases}\Leftrightarrow\hept{\begin{cases}x>-2\\x< 3\end{cases}}\Leftrightarrow-2< x< 3}\)

Vấy -2 < x < 3 thì (x+2)(x-3)<0 

a.\(\left(x-1\right)\left(x+4\right)>0\Leftrightarrow\orbr{\begin{cases}\hept{\begin{cases}x-1>0\\x+4>0\end{cases}}\\\hept{\begin{cases}x-1< 0\\x+4< 0\end{cases}}\end{cases}}\)\(\left(x-1\right)\left(x+4\right)>0\Leftrightarrow\hept{\begin{cases}x-1>0\\x+4>0\end{cases}}\text{ hoặc }\hept{\begin{cases}x-1< 0\\x+4< 0\end{cases}}\) hay \(x>1\text{ hoặc }x< -4\)

b.\(\left(3x-1\right)\left(2x+4\right)\ge0\Leftrightarrow\hept{\begin{cases}3x-1\ge0\\2x+4\ge0\end{cases}}\text{ hoặc }\hept{\begin{cases}3x-1\le0\\2x+4\le0\end{cases}}\) hay ​\(x\ge\frac{1}{3}\text{ hoặc }x\le-2\)

c.\(\left(3-x\right)\left(x+1\right)< 0\Leftrightarrow\hept{\begin{cases}3-x>0\\x+1< 0\end{cases}}\text{ hoặc }\hept{\begin{cases}3-x< 0\\x+1>0\end{cases}}\) hay ​\(-1< x< 3\)

d.\(\left(x-7\right)\left(3x+4\right)\le0\Leftrightarrow\hept{\begin{cases}x-7\ge0\\3x+4\le0\end{cases}}\text{ hoặc }\hept{\begin{cases}x-7\le0\\3x+4\ge0\end{cases}}\) hay ​\(-\frac{3}{4}\le x\le7\)

Uchiha Itachi

số đó là 

2/5.25=10
         Đáp số:10

10 nha bạn

1.I do => I did

2.do => did

3.goes => is going

4.are => \

1. Tìm lỗi :

1, What did you do last night ?I do my home work => did

2, What home do you get up yesterday morning ? => time

3, Where is your mother now ?She goes shopping => is going

4, Which class you are in  ? I'm in class 6B => are you

(10x + 2⁴) . 7⁴ = 2.7⁷

=> 10x + 16 = 2.7⁷ : 7⁴

=> 10x + 16 = 686

=> 10x = 686 - 16

=> 10x = 670

=> x = 67

cảm ơn Nhạt