Gửi bạn nè

ta cos :

\(\left(2x+1\right)^2-2.\left(x-3\right).\left(2x+2\right)+\left(x-3\right)^2\)

\(=\left(2x+1\right)^2-2.\left(2x+1\right).\left(3-x\right)+\left(3-x\right)^2\)

\(=[\left(2x+1\right)-\left(3-x\right)]^2\)

\(=\left(2x+1-3x+x\right)^2\)

\(=\left(3x-2\right)^2\)

Gửi bạn nè. Chúc bạn học tốt !

\(4x^2-25+\left(2x+7\right).\left(5-2x\right)\)

\(=\left(2x+5\right).\left(2x-5\right)-\left(2x+7\right).\left(2x-5\right)\)

\(=\left(2x+5-2x-7\right).\left(2x-5\right)\)

\(=-2.\left(2x-5\right)\)

\(a^2x^2-a^2x^2-b^2x^2+b^2y^2\)

\(=a^2.\left(x^2-y^2\right)-b^2.\left(x^2-y^2\right)\)

\(=\left(a^2-b^2\right).\left(x^2-y^2\right)\)

\(=\left(a-b\right).\left(a+b\right).\left(x-y\right).\left(x+y\right)\)

\(x^2-y^2+12y-36\)

\(=x^2-\left(y^2-12y+36\right)\)

\(=x^2-\left(y-6\right)^2\)

\(=\left(x-y+6\right).\left(x+y-6\right)\)

\(\left(x+2\right)^2-x^2+2x-1\)

\(=\left(x+2\right)^2-\left(x^2-2x+1\right)\)

\(=\left(x+2\right)^2-\left(x-1\right)^2\)

\(=[x+2-\left(x-1\right)].[x+2+\left(x-1\right)]\)

\(=\left(x+2-x+1\right).\left(x+2+x-1\right)\)

\(=3.\left(2x+1\right)\)

\(16x^2-y^2=\left(4x\right)^2-y^2=\left(4x-y\right).\left(4x+y\right)\)

\(1+27x^3=1^3+\left(3x\right)^3=\left(1+3x\right).\left(1-3x+9x^2\right)\)

chỗ AB < AC kia các bn chuyển thành chữ " và " nhé. Mk viết nhầm

1+1=2 nha bạn!

ủa bạn học lớp 8 là có phép tính hay là sao?

2 nha
~HT~