Sửa đề : Giải phương trình

\(3x^2+10x+2=10\)

\(\Leftrightarrow3x^2+10x-8=0\)

\(\Leftrightarrow3x^2+12x-2x-8=0\)

\(\Leftrightarrow3x\left(x+4\right)-2\left(x+4\right)=0\)

\(\Leftrightarrow\left(3x-2\right)\left(x+4\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{2}{3}\\x=-4\end{cases}}\)

Vậy \(S=\left\{-4;\frac{2}{3}\right\}\)

Yêu cầu đề sai nhé.

\(3x^2+10x+2=10\)

\(\Rightarrow3x^2+10x-8=0\)

\(\Rightarrow3\left(x^2+\frac{10x}{3}-\frac{8}{3}\right)=0\)

\(\Rightarrow3\left(x+4\right)\left(x-\frac{2}{3}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=-4\\x=\frac{2}{3}\end{cases}}\)

ủa ủa 

sao lên chửi nhau vậy bạn 

???

Thi sao lien quan den may a

b) \(x\left(5-2x\right)+2x\left(x-1\right)=13\)

\(\Rightarrow5x-2x^2+2x^2-2x=13\)

\(\Rightarrow3x=13\)

\(\Rightarrow x=13:3=\frac{13}{3}\)

c) \(\left(x-2\right)\left(x+5\right)-\left(x-3\right)\left(x+3\right)=5\)

\(\Rightarrow x^2+5x-2x-10-\left(x^2+3x-3x-9\right)=5\)

\(\Rightarrow x^2+5x-2x-10-x^2-3x+3x+9=5\)

\(\Rightarrow3x-1=5\)

\(\Rightarrow3x=6\)

\(\Rightarrow x=6:3=2\)

b) \(x\left(5-2x\right)+2x\left(x-1\right)=13\)

\(\Leftrightarrow5x-2x^2+2x^2-2x=13\)

\(\Leftrightarrow3x=13\)

\(\Leftrightarrow13\div3=\frac{1}{3}\)

\(3\left(x-2\right)+2\left(x-3\right)=5\)

\(\Rightarrow3x-6+2x-6=5\)

\(\Rightarrow\left(3x+2x\right)-\left(6+6\right)=5\)

\(\Rightarrow5x-12=5\)

\(\Rightarrow5x=5+12\)

\(\Rightarrow x=17:5=\frac{17}{5}\)

\(3\left(x-2\right)+2\left(x-3\right)=5\)

\(\Leftrightarrow3x-6+2x-6=5\)

\(\Leftrightarrow\left(3x+2x\right)-\left(6+6\right)=5\)

\(\Leftrightarrow5x-12=5\)

\(\Leftrightarrow5x=5+12\)

\(\Leftrightarrow x=17\div5=\frac{17}{5}\)

5𝑥2−3𝑥−(𝑥3−𝑥2)+𝑥(𝑥2−6𝑥)−10+3𝑥

5x^{2}-3x-\left(x^{3}-x^{2}\right)+x(x^{2}-6x)-10+3x5x2−3x−(x3−x2)+x(x2−6x)−10+3x

5𝑥2−3𝑥−𝑥3+𝑥2+𝑥(𝑥2−6𝑥)−10+3𝑥

X = -10

Mình làm đề theo: Chứng minh biểu thức không phụ thuộc vào biến \(x\), lần sau bạn ghi rõ đề đầy đủ hơn nhé.

\(x\left(5x-3\right)-x^2\left(x-1\right)+x\left(x^2-6x\right)-10+3x\)

\(=5x^2-3x-x^3+x^2+x^3-6x^2-10+3x\)

\(=\left(-x^3+x^3\right)+\left(5x^2+x^2-6x^2\right)+\left(-3x+3x\right)-10\)

\(=0+0+0-10=-10\)