`5(x+5) - 3(x-2) = 5^2 + 18`

`=> 5x + 25 -3x + 6 = 25 + 18`

`=> 5x - 3x = 25 + 18 - 6 - 25`

`=> 2x = 12`

`=> x = 12 : 2`

`=> x = 6`

Vậy `x = 6`

Rất xin lỗi em nhiều về bài làm sai sót của chị ở trên

\(5\left(x+5\right)-3\left(x-2\right)=5^2+18\)

\(\Rightarrow5x+25-3x-6=25+18\)

\(\Rightarrow5x-3x=25+18+6-25\)

\(\Rightarrow2x=24\)

\(\Rightarrow x=24:2\)

\(\Rightarrow x=12\)

Vậy `x = 12`

\(A=1+2+2^2+2^3+2^4+...+2^{19}+2^{20}\)

\(2A=2+2^2+2^3+2^4+2^5+...+2^{20}+2^{21}\)

\(2A-A=\left(2+2^2+2^3+2^4+2^5+...+2^{20}+2^{21}\right)-\left(1+2+2^2+2^3+2^{40}+...+2^{19}+2^{20}\right)\)

\(A=2^{21}-1\)

\(4,32\times1,5+43,2\times0,47+\dfrac{432}{100}\times2,8\)

\(=4,32\times1,5+4,32\times4,7+4,32\times2,8\)

\(=4,32\times\left(1,5+4,7+2,8\right)\)

\(=4,32\times9=38,88\)

`@`Phan Trung Khánh Không được cop Chat GPT nhé!

`-3752 - (29 - 3632) -51`

`= -3752 - 29 + 3632 - 51`

`= (-3752 + 3632) - (29 + 51)`

`= -120 - 80`

`=-200`

Chúc mừg số 1 vs số 4 của danh sách `HTGD` nhe <33

vs cả số `6` vs số `9` trong danh sách nhận giải nhe <3

\(12\%\) của \(150\) là số :

\(\dfrac{12}{100}.150=18\)

Đáp số : `18`

\(b,\sqrt{196}-\sqrt{64}+\sqrt{9}\)

\(=14-8+3\)

\(=6+3\)

\(=9\)

`---`

\(d,\sqrt{289}-\sqrt{144}+\sqrt{\left(-3\right)^2}\)

\(=17-12+\sqrt{9}\)

\(=17-12+3\)

\(=5+3\)

`=8`

\(f,\sqrt{1\dfrac{24}{25}}:1,2-2023^0+\left(-\dfrac{1}{3}\right)^2.\sqrt{\left(-3\right)^2}\)

\(=\sqrt{\dfrac{49}{25}}:\dfrac{6}{5}-1+\dfrac{1}{9}.\sqrt{9}\)

\(=\dfrac{7}{5}:\dfrac{6}{5}-1+\dfrac{1}{9}.3\)

\(=\dfrac{7}{6}-1+\dfrac{1}{3}\)

\(=\dfrac{1}{6}+\dfrac{1}{3}\)

\(=\dfrac{1}{2}\)

${color{#B0E0E6}}{\text{Working}}$

P/S: Nếu ai thấy tớ sai ở đâu thì bảo tớ ạ!

\(a,-\dfrac{3}{4}x-\dfrac{1}{2}=\dfrac{1}{6}\)

\(\Rightarrow-\dfrac{3}{4}x=\dfrac{1}{6}+\dfrac{1}{2}\)

\(\Rightarrow-\dfrac{3}{4}x=\dfrac{2}{3}\)

\(\Rightarrow x=\dfrac{2}{3}:-\dfrac{3}{4}\)

\(\Rightarrow x=-\dfrac{8}{9}\)

Vậy \(x=-\dfrac{8}{9}\)

\(b,\left|x\right|-2,96=\left(-0,2\right)^2\)

\(\Rightarrow\left|x\right|-2,96=0,04\)

\(\Rightarrow\left|x\right|=0,04+2,96\)

\(\Rightarrow\left|x\right|=3\)

\(\Rightarrow x=3\) hoặc \(x=-3\)

Vậy...

\(c,\left|2x-\dfrac{1}{5}\right|=0\)

\(\Rightarrow2x-\dfrac{1}{5}=0\)

\(\Rightarrow2x=0+\dfrac{1}{5}\)

\(\Rightarrow2x=\dfrac{1}{5}\)

\(\Rightarrow x=\dfrac{1}{5}:2\)

\(\Rightarrow x=\dfrac{1}{10}\)

\(d,\)\(\left|x+\dfrac{5}{2}\right|-\dfrac{2}{3}=\left(\dfrac{-1}{2}\right)^3:\left(\dfrac{-1}{2}\right)^2\)

\(\Rightarrow\left|x+\dfrac{5}{2}\right|-\dfrac{2}{3}=-\dfrac{1}{2}\)

\(\Rightarrow\left|x+\dfrac{5}{2}\right|=-\dfrac{1}{2}+\dfrac{2}{3}\)

\(\Rightarrow\left|x+\dfrac{5}{2}\right|=\dfrac{1}{6}\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{5}{2}=\dfrac{1}{6}\\x+\dfrac{5}{2}=-\dfrac{1}{6}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{6}-\dfrac{5}{2}\\x=-\dfrac{1}{6}-\dfrac{5}{2}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{3}\\x=-\dfrac{8}{3}\end{matrix}\right.\)

Vậy \(x\in\left\{-\dfrac{7}{3};-\dfrac{8}{3}\right\}\)

P/S : Nếu tớ sai ở đâu thì mọi người góp ý giúp ạ!

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