vippro
Giới thiệu về bản thân
tôi đẹp trai
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2024-11-07 13:08:13
chịu
2024-11-07 12:57:23
2024-11-07 12:48:28
=7
2024-11-06 21:46:55
2024-11-06 21:43:37
C = \(\dfrac{x+1}{x-2}\) (\(x\)≠ 2)
C \(\in\) Z ⇔ \(x+1\) ⋮ \(x-2\)
\(x\) - 2 + 3 ⋮ \(x-2\)
3 ⋮ \(x-2\)
\(x-2\) \(\in\) Ư(3) = [-3; -1; 1 ;3}
\(x\) \(\in\) {-1; 1; 3; 5}
Vậy \(x\) \(\in\) {-1; 1; 3; 5}
2024-11-06 21:39:27
tui lớp 7 nè
2024-11-06 21:34:38
A
2024-11-06 21:27:48
lớp 7 thì sao????????
2024-11-06 21:17:17
3
2024-11-05 22:40:41
chịu