Đỗ Đức Hiển
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2024-10-14 17:07:49
a)\(\dfrac{x+6}{x+5}\)+\(\dfrac{3}{2}\)=2
\(\dfrac{2x+12}{2x+10}\)+\(\dfrac{3x+15}{2x+10}\)=\(\dfrac{4x+20}{2x+10}\)
2x+12+3x+15=4x+20
x+7=0
x=-7
2024-10-14 17:03:50
2024-10-14 16:51:50
a) \(\dfrac{x+6}{x+5}\)+\(\dfrac{3}{2}\)=2
\(\dfrac{2x+12}{2x+10}\)+\(\dfrac{3x+15}{2x+10}\)==\(\dfrac{4x+20}{2x+10}\)
2x+12+3x+15=4x+20
x+7=0
x=-7
2024-10-14 16:51:50
a) \(\dfrac{x+6}{x+5}\)+\(\dfrac{3}{2}\)=2
\(\dfrac{2x+12}{2x+10}\)+\(\dfrac{3x+15}{2x+10}\)==\(\dfrac{4x+20}{2x+10}\)
2x+12+3x+15=4x+20
x+7=0
x=-7
2024-10-14 16:41:57