Đào Nguyễn Trà Vy
Giới thiệu về bản thân
a) \(x+\dfrac{2}{5}=\dfrac{-4}{3}\)
\(x=\dfrac{-4}{3}-\dfrac{2}{5}\)
\(x=\dfrac{-26}{15}\)
b) \(\dfrac{-5}{6}+\dfrac{1}{3}.x=\left(\dfrac{-1}{2}\right)^2\)
\(\dfrac{-5}{6}+\dfrac{1}{3}.x=\dfrac{1}{4}\)
\(\dfrac{1}{3}.x=\dfrac{1}{4}-\dfrac{-5}{6}\)
\(\dfrac{1}{3}.x=\dfrac{13}{12}\)
\(x=\dfrac{13}{12}:\dfrac{1}{3}\)
\(x=\dfrac{13}{4}\)
c) \(\dfrac{7}{12}-\left(x+\dfrac{7}{6}\right).\dfrac{6}{5}=\left(\dfrac{-1}{2}\right)^3\)
\(\dfrac{7}{12}-\left(x+\dfrac{7}{6}\right).\dfrac{6}{5}=\dfrac{-1}{8}\)
\(\left(x+\dfrac{7}{6}\right).\dfrac{6}{5}=\dfrac{7}{12}-\dfrac{-1}{8}\)
\(\left(x+\dfrac{7}{6}\right).\dfrac{6}{5}=\dfrac{17}{24}\)
\(x+\dfrac{7}{6}=\dfrac{17}{24}:\dfrac{6}{5}\)
\(x+\dfrac{7}{6}=\dfrac{85}{144}\)
\(x=\dfrac{85}{144}-\dfrac{7}{6}\)
\(x=\dfrac{-83}{144}\)