cho 13g kẽm tác dụng với HCl theo phương trình Zn + HCl ---> ZnCl2 + H2 a) tính số mol kẽm b) tính thể tích H2 c) tinhs khối lượng axit đã dùng
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1. In my family, children has to get permission before leaving the dinning table.
=> In my family, children have to get permission before leaving the dinning table.
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4. When you visit temple in Thailand, you have to following some important customs.
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5. People should to lower their voice inside the temple.
=> People should lower their voice inside the temple.
1. - đơn chất: H2
- hợp chất:H2O,C12H22O11,Al2O3,CaCO3,CO2
2.
Nguyên tố | Kí hiệu hoá học |
---|---|
Natri | Na |
Lưu huỳnh | S |
Bari | Ba |
Magie | Mg |
Bạc | Ag |
3.
a) PTK(CO2): 12+16\(\times\)2 =44 đvC
b) PTK(H2SO4): 1\(\times\)2+32+16\(\times\)4 =98 đvC
c) PTK(CuSO4): 64+32+16\(\times\)4 =160 đvC
a)V\(_{H_2}\)=0,35 x 22,4=7,84(lít)
b)n\(_{CO_2}\)=\(\frac{15,84}{44}\)=0,36(mol)
V\(_{CO_2}\)=0,36 x 22,4 =8,064(lít)
e)n\(_{SO_2}\)=\(\frac{55,04}{64}\)=0,86(mol)
V\(_{SO_2}\)=0,86 x 22,4=19,264(lít)
Còn 2 câu kia tôi chịu
a)n\(_{Cu}\)=\(\frac{m}{M}\)=\(\frac{9,6}{64}\)=0,15(mol)
b)n\(_{CaCO_3}\)=\(\frac{m}{M}\)=\(\frac{10}{100}\)=0,1(mol)
c)n\(_{H_2SO_4}\)=\(\frac{19,6}{98}\)=0,2(mol)
d)n\(_{Ba}\)=\(\frac{30,14}{137}\)=0,22(mol)
TL
a) n = 9,6 : 64 = 0,15 (mol)
b) n = 10 : 100 = 0,1 (mol)
c) n = 19,6 : 98 = 0,2 (mol)
d) n = 30,14 : 137 = 0,22 (mol)
Khi nào rảnh vào kênh H-EDITOR xem vid nha!!! Thanks!
mik cũng ko bt đúng hay sai
Zn + 2HCl -> ZnCl2 + H2
a)nZn=\(\frac{13}{65}\)=0,2(mol)
Theo PTHH ta có:
nH2=nZn=0,2(mol)
nHCl=2nZn=0,4(mol)
b)VH2=22,4.0,2=4,48(lít)
c)mHCl=36,5.0,4=14,6(g)