Mn giúp e với ạ huhu, sắp đến hạn r ạ :<
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N2+3H2to,xt,p⇌2NH3N2+3H2⇌to,xt,p2NH3
Ta thấy : VN2:1>VH2:3VN2:1>VH2:3 nên N2N2 dư
Gọi hiệu suất là a
Suy ra : VH2 pư=11,2a(lít)VH2 pư=11,2a(lít)
VN2 pư=11,2a3VN2 pư=11,2a3
VNH3=2.11,2a3VNH3=2.11,2a3
Ta có :
![](https://rs.olm.vn/images/avt/0.png?1311)
Vì khí CO2 nặng hơn không khí 1,52 lần nên khí CO2 thường tích tụ trong đáy giếng khơi, trên nền hang sâu.
Vì khí CO2 nặng hơn không khí 1,52 lần nên khí CO2 thường tích tụ trong đáy giếng khơi, trên nền hang sâu.
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Zn + 2HCl -> ZnCl2 + H2
a)nZn=\(\frac{13}{65}\)=0,2(mol)
Theo PTHH ta có:
nH2=nZn=0,2(mol)
nHCl=2nZn=0,4(mol)
b)VH2=22,4.0,2=4,48(lít)
c)mHCl=36,5.0,4=14,6(g)
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1.has=>have
2.is=>was
3.was=>was being
4.following=>follow
5.to lower=>lower
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1. In my family, children has to get permission before leaving the dinning table.
=> In my family, children have to get permission before leaving the dinning table.
2. When I came, the whole family is having dinner around a big dinning table
=> When I came, the whole family was having a dinner around a big dinning table.
3. Lang Lieu couldn't buy any special food while he was very poor.
= > Lang Lieu couldn't buy any special food when he was very poor.
4. When you visit temple in Thailand, you have to following some important customs.
=> When you visit a temple in Thailand, you have to follow some important customs.
5. People should to lower their voice inside the temple.
=> People should lower their voice inside the temple.
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1. - đơn chất: H2
- hợp chất:H2O,C12H22O11,Al2O3,CaCO3,CO2
2.
Nguyên tố | Kí hiệu hoá học |
---|---|
Natri | Na |
Lưu huỳnh | S |
Bari | Ba |
Magie | Mg |
Bạc | Ag |
3.
a) PTK(CO2): 12+16\(\times\)2 =44 đvC
b) PTK(H2SO4): 1\(\times\)2+32+16\(\times\)4 =98 đvC
c) PTK(CuSO4): 64+32+16\(\times\)4 =160 đvC
\(n_X=\frac{5,6}{22,4}=0,25mol\)
Đặt \(\hept{\begin{cases}n_{H_2S}=a\\n_{CH_4}=b\end{cases}}\)
\(\Rightarrow a+b=n_C=0,25mol\)
\(m_X=m_{H_2S}+m_{CH_4}=34a+16b=5,8\)
\(\Rightarrow\hept{\begin{cases}a=0,1mol\\b=0,15mol\end{cases}}\)
Bảo toàn nguyên tố H: \(n_H=2n_{H_2S}=0,2mol;n_H=4n_{CH_4}=0,6mol\)
\(\Rightarrow\text{Σ}n_H=0,2+0,6=0,8mol\)
\(\Rightarrow m_H=0,8.1=0,8g\)