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4/28 + 4/168 + 4/408 + 4/748 + 4/1188 + 4/1728
= 1/7 + 1/42 + 1/102 + 1/187 + 1/297 + 1/432
= 1/7 + 1/7.6 + 1/6.17 + 1/17.11 + 1/11.27 + 1/27.16
= 1/7(1 + 1/6) + 1/17(1/6 + 1/11) + 1/27(1/11 + 1/16)
= 1/7.7/6 + 1/17.17/66 + 1/27.27/176
= 1/6 + 1/66 + 1/176
= 12/66 + 1/176
= 3/16

`Answer:`
a. \(-\frac{13}{31}:\frac{5}{7}+\left(-\frac{18}{31}\right):\frac{5}{7}=\left(-\frac{13}{31}+-\frac{18}{31}\right):\frac{5}{7}=-1:\frac{5}{7}=-\frac{7}{5}\)
b. \(0,5+\frac{1}{3}+0,4+\frac{5}{7}+\frac{1}{6}-\frac{4}{35}\)
\(=\frac{1}{2}+\frac{1}{3}+\frac{2}{5}+\frac{5}{7}+\frac{1}{6}-\frac{4}{35}\)
\(=\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\right)+\left(\frac{2}{5}+\frac{5}{7}-\frac{4}{35}\right)\)
\(=1+1\)
\(=2\)
c. \(-1.2.3.4...9+1.2.3...8+1.2.3...8^2\)
\(=-1.2.3.4...9+1.2.3...8.\left(1+8\right)\)
\(=-1.2.3.4...9+1.2.3...8.9\)
\(=0\)

\(a)\frac{-2}{3}\cdot\frac{5}{17}+\frac{-2}{3}\cdot\frac{12}{17}+\frac{2}{3}\)
\(=\frac{-2}{3}\cdot\frac{5}{17}+\frac{-2}{3}\cdot\frac{12}{17}+\frac{-2}{3}\cdot\left(-1\right)\)
\(=\frac{-2}{3}\cdot\left[\frac{5}{17}+\frac{12}{17}+\left(-1\right)\right]\)
\(=\frac{-2}{3}\cdot0\)
\(=0\)
\(b)\frac{3}{4}\cdot\frac{9}{13}+\frac{3}{4}\cdot\frac{7}{13}-\frac{3}{14}\cdot\frac{3}{13}\)
\(=\frac{3}{4}\cdot\left(\frac{9}{13}+\frac{7}{13}-\frac{3}{13}\right)\)
\(=\frac{3}{4}\cdot1\)
\(=\frac{3}{4}\)
\(c)\frac{-7}{12}\cdot\frac{5}{11}+\frac{-7}{12}\cdot\frac{5}{11}-\frac{1}{3}\)
\(=\frac{-7}{12}\cdot\left(\frac{5}{11}+\frac{5}{11}\right)-\frac{1}{3}\)
\(=\frac{-7}{12}\cdot\frac{10}{11}-\frac{1}{3}\)
\(=\frac{-35}{66}-\frac{1}{3}\)
\(=\frac{-57}{66}\)
\(d)\frac{-1}{5}\cdot\frac{4}{7}+\frac{-1}{5}\cdot1\frac{3}{7}+\left(\frac{-2}{5}\right)^1\)\
\(=\frac{-1}{5}\cdot\frac{4}{7}+\frac{-1}{5}\cdot\frac{10}{7}+\frac{-2}{5}\)
\(=\frac{-1}{5}\cdot\frac{4}{7}+\frac{-1}{5}\cdot\frac{10}{7}+\frac{-1}{5}\cdot2\)
\(=\frac{-1}{5}\cdot\left(\frac{4}{7}+\frac{10}{7}+2\right)\)
\(=\frac{-1}{5}\cdot4\)
\(=\frac{-4}{5}\)
ủa sao ko ai trả lời v ạ
em mà hc lớp 6 thì em đã giúp
em mới hc lớp 5

`Answer:`
1.
\(A=\frac{1}{4}+\frac{2}{3}=\frac{3}{12}+\frac{8}{12}=\frac{11}{12}\)
\(B=\frac{3}{5}.\frac{5}{4}-\frac{3}{5}.\frac{1}{4}=\frac{3}{5}.\left(\frac{5}{4}-\frac{1}{4}\right)=\frac{3}{5}\)
2.
\(x-\frac{7}{13}=-\frac{21}{13}\)
\(\Leftrightarrow x=\left(-\frac{21}{13}\right)-\frac{7}{13}\)
\(\Leftrightarrow x=-\frac{14}{13}\)
\(\frac{1}{4}x-6\frac{2}{5}=3,75\)
\(\Leftrightarrow0,25x-6,4=3,75\)
\(\Leftrightarrow0,25x=3,75+6,4\)
\(\Leftrightarrow0,25x=10,15\)
\(\Leftrightarrow x=10,15:0,25\)
\(\Leftrightarrow x=40,6\)

D
211,6