(a^m)^n= a^m. a^m....a^m( n số)= (a.a.a...a).(a.a.a.a...a)......(a.a.a..a)(có n tích a.a...a, có m atrong 1 tích)

=> (a.a...a)......(a.a...a) = a.a.a.a.....a => số số a nhân với nhau sẽ bằng m.n = a^ m.n

a^n .b^n = a.a.a...a(n số) . b.b...b ( n số) = (a.b) . (a.b)....(a.b) (n tích ) => = (a.b)^n

( x - 289 ) . 47 = 0

x - 289 = 0 : 47

x - 289 = 0

         x = 0 + 289

         x = 289

(x - 289) . 47 = 0

=> x - 289 = 0

=> x = 289

\(A=2+2^2+2^3+....+2^{60}\)

\(A=\left(2+2^2+2^3+2^4\right)+....+\left(2^{57}+2^{58}+2^{59}+2^{60}\right)\)

\(A=2.\left(1+2+2^2+2^3\right)+....+2^{57}.\left(1+2+2^2+2^3\right)\)

\(A=2.15+.....+2^{57}.15\)

\(A=15.\left(2+.......+2^{57}\right)\)

Do \(15⋮15\)

\(\Rightarrow15.\left(2+.....+2^{57}\right)⋮15\)

\(\Rightarrow A⋮15\)

Ta có: 

A = 2 + 2² + 2³ + ... + 2⁶⁰

A = (2 + 2² + 2³ + 2⁴) + (2⁵ + 2⁶ + 2⁷ + 2⁸) + ... + (2⁵⁷ + 2⁵⁸ + 2⁵⁹ + 2⁶⁰)

A = 2 . (1 + 2 + 2² + 2³) + 2⁵ . (1 + 2 + 2² + 2³) + ... + 2⁵⁷ . (1 + 2 + 2² + 2³) 

A = 2 . 15 + 2⁵ . 15 + ... + 2⁵⁷ . 15

A = 15 . (2 + 2⁵ + ... + 2⁵⁷)

Vì 15 . (2 + 2⁵ + ... + 2⁵⁷) chia hết cho 15 nên A chia hết cho 15.

 suy ra: (x +35) =515 :5

 suy ra;    x +35=103

 suy ra:           x=103-35

suy ra:              Vậy x=68

đúng nha!!!!!! 100% lun!!!!!!!! !!!!!!!!!!

5(x+35) = 515

x + 35 = 515 : 5

x + 35 = 103

       x  = 103 - 35

       x  = 68

a) x = 2

b) x = 8

c) x = 1 hoặc x = 0

a) 2⁴ = x⁴
\(\Rightarrow\)x = 2
b) 3^x = 3⁸
\(\Rightarrow\)x = 8
c) x⁴⁰ = x
\(\Rightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}\)

3x - 7 = 2^2 . 3^2

3x - 7 = 36

3x = 36 + 7 

3x = 43

x = 43 : 3

x = 43/3

3x - 7 = 2² . 3²

3x - 7 = 4 . 9

3x - 7 = 36

3x = 36 + 7

3x = 43

  x = 43 : 3

  x = \(\frac{43}{3}\)

\(2^{10}\)có 4 chữ số

nhan voi nhau hay the nao?

db ko hiu j ca

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