\(5^{x+1}+6.5^{x+1}=875\)

\(\Rightarrow5^{x+1}.\left(1+6\right)=875\)

\(\Rightarrow5^{x+1}.7=875\)

\(\Rightarrow5^{x+1}=875:7=125\)

\(\Rightarrow5^{x+1}=5^3\)

\(\Rightarrow x+1=3\)

\(\Rightarrow x=3-1=2\)

khong biet

3^x + 3^x+3 = 756

=> 3^x + 3^x.3³ = 756

=> 3^x + 3^x.27 = 756

=> 3^x.(27+1) = 756

=> 3^x.28 = 756

=> 3^x = 756 : 28

=> 3^x = 27 = 3³

=> x = 3 

\(9^x:3^{x=3}\)

\(\left(9:3\right)^x=3\)

\(3^x=3\)

\(\Rightarrow x=1\)

=> (9:3)^x=3¹

=> 3^x=3¹

=> x=1

chào bạn kb nhé

minh giai nhu the nay xem dung ko nha:

x se la mu  2 :

nhu vay ta se duoc : 

\(\left(-8\right)^2\) = 64 { vi (- 8) . (- 8) = 64 vi am nham voi am se ra duong }

tuong tu : \(13^2\)= 169  ( vi 13 .13 = 169 )

 nen ta co  \(\frac{64}{169}=\frac{64}{169}\)

nen ta => so nguyen x con co the noi la mu x = 2

vay \(\frac{64}{169}=\left(-\frac{8}{13}\right)^2\)

8/125 = 2^x/5^x

Ta có: 8=2.2.2=2³

125=5.5.5=5³

=> 8/125=2³/5³

=>x=3

(1/16)^x=(1/2)¹⁰

Mà: (1/16)^x=((1/2)⁴)^x

=>4.x=10

=>x=10:4

=>x=2,5

(1/16)^x  = ((1/2)⁴)^x

4 . x = 10

x = 10:4

 x = 2,5

\(\left(2x+1\right)^5=\left(2x+1\right)^{2010}\)

\(\Rightarrow\left(2x+1\right)^{2010}-\left(2x+1\right)^5=0\)

\(\Rightarrow\left(2x+1\right)^5.\left[\left(2x+1\right)^{2005}-1\right]=0\)

\(\Rightarrow\orbr{\begin{cases}\left(2x+1\right)^5=0\\\left(2x+1\right)^{2005}-1=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}2x+1=0\\\left(2x+1\right)^{2005}=1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}2x+1=0\\2x+1=1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}2x=-1\\2x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=0\end{cases}}\)

Vậy \(\orbr{\begin{cases}x=-\frac{1}{2}\\x=0\end{cases}}\)

(2x+1)⁵=(2x+1)²⁰¹⁰

=> 2x+1=1 hoặc 2x+1=0

=>2x=0  hoặc 2x=1

=>x=0 hoặcx=0,5

\(\left(2x-3\right)^4=81\)

\(< =>\left(2x-3\right)^4=3^4\)hoặc \(< =>\left(2x-3\right)^4=\left(-3\right)^4\)

\(< =>2x-3=3\)         hoặc \(< =>2x-3=3\)

\(< =>2x=6\)                 hoặc  \(< =>2x=0\)

\(< =>x=3\)                   hoặc   \(< =>x=0\)

   Vậy \(x=3\)hoặc \(x=0\)

(2x-3)⁴=81

Mà: 3⁴=81 và (-3)⁴=81

=> (2x-3)⁴=3⁴ hoặc (2x-3)⁴=(-3)⁴

=> 2x-3=3 hoặc 2x-3= -3

=> 2x=6 hoặc 2x=0

=>x=3 hoặc x=0

\(\left(2x+1\right)^3=-0,001\)

\(\Rightarrow\left(2x+1\right)^3=\left(-0,1\right)^3\)

\(\Rightarrow2x+1=-0,1\)

\(\Rightarrow2x=-\frac{1}{10}-1\)

\(\Rightarrow2x=-\frac{11}{10}\)

\(\Rightarrow x=-\frac{11}{10}:2\)

\(\Rightarrow x=-\frac{11}{10}.\frac{1}{2}=-\frac{11}{20}\)

-11/20