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\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0.\)
\(TH1:3x-1=0\)
\(3x=0+1\)
\(3x=1\)
\(x=\frac{1}{3}\)
\(TH2:\frac{-1}{2}x+5=0\)
\(\frac{-1}{2}x=-5\)
\(x=-5\div\frac{-1}{2}\)
\(x=10\)
\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0.\)
TH1:
\(3x-1=0\)
\(3x=0+1\)
\(3x=1\)
\(x=1\div3\)
\(x=\frac{1}{3}\)
TH2:
\(\frac{-1}{2}x+5=0\)
\(\frac{-1}{2}x=0-5\)
\(\frac{-1}{2}x=-5\)
\(x=-5\div\frac{-1}{2}\)
\(\Leftrightarrow x=-5.\left(-2\right)\)
\(x=10\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{3}\\x=10\end{cases}}\)
a) \(\frac{-1}{2}+\frac{5}{6}+\frac{1}{3}=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}.\)
b) \(\frac{-3}{8}+\frac{7}{4}+\frac{1}{12}=\frac{3}{8}+\frac{1}{12}=\frac{36}{96}+\frac{8}{96}=\frac{48}{96}=\frac{1}{2}\)
c) \(\frac{3}{5}\div\left(\frac{1}{4}\div\frac{7}{5}\right)=\frac{3}{5}\div\frac{5}{28}=\frac{3}{5}.\frac{28}{5}=\frac{84}{25}\)
d) \(\frac{10}{11}+\frac{4}{11}\div4-\frac{-1}{8}=\left(\frac{14}{11}\div4\right)-\frac{-1}{8}=\frac{7}{22}-\frac{1}{8}=\frac{56}{176}-\frac{22}{176}=\frac{34}{176}=\frac{17}{88}\)
e) \(\frac{5}{13}.\frac{8}{15}+\frac{5}{13}.\frac{26}{15}-\frac{5}{13}.\frac{8}{15}=\frac{5}{13}.\left(\frac{8}{15}+\frac{26}{15}-\frac{8}{15}\right)=\frac{5}{13}.\frac{26}{15}=\frac{130}{195}=\frac{26}{39}\)
\(\frac{5}{6}+\frac{7}{13}+\frac{17}{9}+\frac{19}{13}+\frac{1}{9}+\frac{7}{6}\)
\(=\left(\frac{5}{6}+\frac{7}{6}\right)+\left(\frac{17}{9}+\frac{1}{9}\right)+\left(\frac{19}{13}+\frac{7}{13}\right)\)
\(=\frac{12}{6}+\frac{18}{9}+\frac{26}{13}\)
\(=2+2+2\)
\(=4+2\)
\(=6\)
\(\frac{5}{6}+\frac{7}{13}+\frac{17}{9}+\frac{19}{13}+\frac{1}{9}+\frac{7}{6}.\)
\(=\left(\frac{5}{6}+\frac{7}{6}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{17}{9}+\frac{1}{9}\right)\)
\(=\frac{12}{6}+\frac{26}{13}+\frac{18}{9}\)
\(=2+2+2\)
\(=6\)
Tổng số lít nước là : \(24\times120=2880\text{ lít}\)
Nếu mỗi thùng chứa được 160 lít nước thì số thùng cần để chứa nước là :
\(2880:160=18\text{ thùng}\)
Tuổi em là: (20-8):2=6(tuổi)
Tuổi anh là:20-6=14(tuổi)
Đáp số:anh:14 tuổi
em:6 tuổi
\(\left(2x+\frac{3}{5}\right)^3+\frac{8}{125}=0\)
\(\left(2x+\frac{3}{5}\right)^3=0-\frac{8}{125}\)
\(\left(2x+\frac{3}{5}\right)^3=-\frac{8}{125}\)
\(\frac{1}{125}\left(10x+3^3\right)=-\frac{8}{125}\)
\(\Rightarrow x=\frac{-1}{2}\)
`Answer:`
\(\left(2x+\frac{3}{5}\right)^3+\frac{8}{125}=0\)
\(\Rightarrow\left(2x+\frac{3}{5}\right)^3=-\frac{8}{125}\)
\(\Rightarrow\left(2x+\frac{3}{5}\right)^3=\left(-\frac{2}{5}\right)^3\)
\(\Rightarrow2x+\frac{3}{5}=-\frac{2}{5}\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=-\frac{1}{2}\)