TL:

Đặt A=(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)A=(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)

⇒2A=(3−1)(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)⇒2A=(3−1)(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)

=(32−1)(32+1)(34+1)(38+1)(316+1)(332+1)=(32−1)(32+1)(34+1)(38+1)(316+1)(332+1)

=...........................................=...........................................

=(332−1)(332+1)=364−1=(332−1)(332+1)=364−1

⇒A=364−122

k cho mk nha

HT

\(3x\left(x-2\right)=3x^2-6x\)

\(\left(3x-1\right)\left(x+2\right)=3x^2-x+6x-2=3x^2+5x-2\)

\(5x^2\)\(-15x+5+x-5x^2\)\(=x-2\)

\(-15x+5=-2\)

\(-15x=-2-5=-7\)

\(x=-7:-15=\frac{-7}{-15}\)\(=\frac{7}{15}\)

\(x=\frac{7}{15}\)

\(x(x-5)(x+5)-(x+2)(x^2-2x+4)\)

\(\Leftrightarrow x(x^2-25)-(x^3+8)\)

\(\Leftrightarrow x^3-25x-x^3-8\)

\(\Leftrightarrow-25x=11\Leftrightarrow x=-\frac{11}{25}\)

\(x\left(x-5\right)\left(x+5\right)-\left(x+2\right)\left(x^2-2x+4\right)\)

\(\rightarrow\)\(x\left(x^2-25\right)-\left(x^3+8\right)\)

\(\rightarrow\)\(x^3-25x-x^3-8\)

\(\rightarrow\)\(-25x=11\Leftrightarrow x=-\frac{11}{25}\)

x ( x-5) (x+5) -(x+2)(x² -2x +4 ) =17

x. (x² -25) - ( x³ + 8 ) =17

x³ -25x -x³ -8 =17

-25x -8 =17

-25x = 25

x=-1

vậy x =-1