Câu hỏi của lalashijdhvkjsvdskjjksnfks

Question

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Nguyễn Lê Phước Thịnh · Accepted Answer

1: $A=\sqrt{\dfrac{16}{25}}\cdot\sqrt{\dfrac{25}{16}}+\sqrt{\dfrac{49}{81}}:\sqrt{\dfrac{4}{9}}-\left(-\dfrac{1}{2}\right)^3$

$=1+\dfrac{7}{9}:\dfrac{2}{3}+\dfrac{1}{8}$

$=\dfrac{9}{8}+\dfrac{7}{9}\cdot\dfrac{3}{2}$

$=\dfrac{9}{8}+\dfrac{7}{6}=\dfrac{54+56}{48}=\dfrac{110}{48}=\dfrac{55}{24}$

Câu trả lời:

1: $A=\sqrt{\dfrac{16}{25}}\cdot\sqrt{\dfrac{25}{16}}+\sqrt{\dfrac{49}{81}}:\sqrt{\dfrac{4}{9}}-\left(-\dfrac{1}{2}\right)^3$

$=1+\dfrac{7}{9}:\dfrac{2}{3}+\dfrac{1}{8}$

$=\dfrac{9}{8}+\dfrac{7}{9}\cdot\dfrac{3}{2}$

$=\dfrac{9}{8}+\dfrac{7}{6}=\dfrac{54+56}{48}=\dfrac{110}{48}=\dfrac{55}{24}$

x	10	-2	-3	1	0	1.21	0.25
\(^{x^2}\)	100	4	9	1	0	1.4641	0.0625

1.44	-25	\(\dfrac{4}{9}\)
2.0736	625	\(\dfrac{16}{81}\)