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a.\(6x^2-\left(2x-3\right)\left(3x+2\right)-1=0\Leftrightarrow6x^2-\left(6x^2-2x-6\right)-1=0\)
\(\Leftrightarrow2x+5=0\Leftrightarrow x=-\frac{5}{2}\)
b. \(\left(x-3\right)\left(x+7\right)-\left(x+5\right)\left(x-1\right)=0\Leftrightarrow x^2+4x-21-\left(x^2+4x-5\right)=0\)
\(\Leftrightarrow-16=0\)
Vậy không có x thỏa mãn.
a, <=> 2,5 : 4x = 2,5
<=> 4x = 2,5 : 2,5 = 1
<=> x=1 : 4 = 1/4
b, <=> 1/5.x:3 = 8/3
<=> 1/5.x = 8/3 . 3 = 8
<=> x = 8 : 1/5 = 40
\(70:\frac{4x+720}{x}=\frac{1}{2}\)
\(\frac{4x+720}{x}=70:\frac{1}{2}\)
\(\frac{4x+720}{x}=140\)
\(4x+720=140x\)
\(4x-140x=-720\)
\(-136x=-720\)
\(x=\frac{-720}{-136}\)
\(x=\frac{90}{17}\)
\(\frac{70x}{4x+720}=\frac{1}{2}\)
\(140x=4x+720\)
\(136x=720\)
\(x=720:136\)
\(x=\frac{90}{17}\)
Ta có \(2x^2-2xy=5x-y-19\Leftrightarrow2x^2-5x+19=2xy-y\)
<=>\(\frac{2x^2-5x+19}{2x-1}=y\)
Mà y là số nguyên =>\(\frac{2x^2-5x+19}{2x-1}\in Z\Leftrightarrow\frac{2x^2-x-4x+2+17}{2x-1}\in Z\)
\(\Leftrightarrow2x-2+\frac{17}{2x-1}\in Z\Leftrightarrow\frac{17}{2x-1}\in Z\Rightarrow17⋮2x-1\)
đến đây lấp bảng nhé !
^_^
\(\left|x+\frac{4}{15}\right|-\left|-3.75\right|=-\left|-2,15\right|\)
\(\Rightarrow\left|x+\frac{4}{15}\right|-\frac{15}{4}=-\frac{43}{20}\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=-\frac{43}{20}+\frac{15}{4}\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=-\frac{8}{5}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{4}{3}\\x=-\frac{28}{15}\end{cases}}\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=1,6\)
=> \(x+\frac{4}{15}=1,6\) hoặc \(x+\frac{4}{15}=-1,6\)
=> \(x=\frac{4}{3}\) hoặc \(x=\frac{-28}{15}\)
Vậy..
\(B=\left|x+3\right|+\left|2-x\right|\ge\left|x+3+2-x\right|=\left|5\right|=5\)
Dấu "=" xảy ra khi \(x=0\)
Vậy \(B_{min}=5\Leftrightarrow x=0\)
c)3(2x-1)-5(x-3)+6(3x-4)=24
<=>6x-3-5x-15+18x-24=24
<=>19x-12=24
<=>19x=36
<=>x=\(\frac{36}{19}\)
d)2x(5-3x)+2x(3x-5)-3(x-7)=3
<=>10x-6x2+6x2-10x-3x-21=3
<=>-3(x-7)=3
<=>21-3x=3
<=>-3x=-18
<=>x=6
0,1(6):x=0,(33)
=>[0,1+0,0(6)]:x=33/99=1/3
=>(1/10+1/15):1/3=x
=>1/6.3=x
=>x=3/6=1/2=0,5
nhớ tick nhé
Ta có: \(0,1\left(6\right)=0,1+0,0\left(6\right)=0,1+\frac{1}{10}.0,\left(6\right)=0,1+\frac{1}{10}.6.0,\left(1\right)=0,1+\frac{1}{10}.6.\frac{1}{9}=\frac{1}{6}\)\(0,\left(33\right)=33.0,\left(01\right)=33.\frac{1}{99}=\frac{1}{3}\)
\(\Rightarrow\frac{1}{6}:x=\frac{1}{3}\Rightarrow x=\frac{1}{6}:\frac{1}{3}=\frac{1}{2}\)
0,25 : x = x : 16
=> 0,25 .16 = x2
x2 = 64 = 82 = (-8)2
=> x = 8 hoặc x = -8
0,25.x=x:16
x²=0.25.16
x²=4
x²=2²=(-2)²
=>x=2 hoặc x=-2
Vậy x=\(\pm\)2