A. behaved B. bored C. hoped D. tried
Gạch ngang ở dưới là ed nha(mk ko biết gõ, sorry)
Mn giúp mk câu này vs ạ,mk cảm ơn!
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
23. Please take the form from your teacher and ask her to sign.
24. Can you show me the nearest way to the post office
25. We are going to plant the flowers in the parks and water them in the afternoon.
26. My brother is very good at repairing household appliances.
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
Program hotrotinhoc;
var i: byte;
begin
write('5 so tu nhien dau tien la : ');
for i:=0 to 4 do write(i,' ');
readln
end.
Bài 3:
Program hotrotinhoc;
var n,i: integer;
s: real;
begin
write('N='); readln(n);
i:=0;
while i<n do
begin
inc(i);
s:=s+1/i;
end;
write('S=',s:1:2);
readln
end.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\dfrac{7}{12}-\left(x+\dfrac{7}{10}\right):\dfrac{6}{5}=\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{7}{12}-x-\dfrac{7}{10}:\dfrac{6}{5}=\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{7}{12}-x-\dfrac{7}{12}=\dfrac{5}{4}\)
\(\Leftrightarrow\dfrac{7}{12}-x=\dfrac{5}{4}+\dfrac{7}{12}\)
\(\Leftrightarrow\dfrac{7}{12}-x=\dfrac{11}{6}\)
\(\Leftrightarrow x=\dfrac{7}{12}-\dfrac{11}{6}\)
\(\Leftrightarrow\dfrac{-5}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
part 1
1 which
2 won't
3 because
4 Good idea
5 on
6 therefore
part 2
1D 2F 3A 4B 5C 6E
part 3
1 studied
2 has worked
3 being interviewed
4 to be taken
5 would visit
6 put
7 endangered
8 compulsorily
part 4
1 are -> is
2 me -> to me
3 work -> working
4 when -> since
part 5
1 written novels for
2 to read bedtime stories
3 to wearing
4 has been absent from
5 doesn't have a passport
6 were given to Martha
7 play football that
8 whom my teacher was
part 6
1 mankind
2 polluted
3 of
4 naturally
part 7
1F 2F 3T 4T
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 3 :
\(\%N_{\left(NH_4Cl\right)}=\dfrac{14}{53.5}\cdot100\%=26.16\%\)
\(\%N_{\left(\left(NH_4\right)_2SO_4\right)}=\dfrac{14\cdot2}{132}\cdot100\%=21.21\%\)
\(\%N_{\left(\left(NH_2\right)_2CO\right)}=\dfrac{14\cdot2}{56}\cdot100\%=50\%\)
Khi đó : lượng đạm (N) trong (NH2)2CO là lớn nhất
Đúng là N trong (NH2)2CO cao nhất nhưng bạn Quang Nhân đang nhầm PTK của hợp chất đó nên tính phần trăm sai em ạ!
\(\%m_{\dfrac{N}{\left(NH_2\right)_2CO}}=\dfrac{2.14}{\left(2.1+14\right).2+12+16}.100\approx46,667\%\)
C
thx bạn