x+2014 /2 +2x+4028/7=x+2014/5+x+2014/6
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\(\dfrac{x+2014}{2}+\dfrac{2\left(x+2014\right)}{7}=\dfrac{x+2014}{5}+\dfrac{x+2014}{6}\)
\(\left(x+2014\right)\left(\dfrac{1}{2}+\dfrac{2}{7}\right)=\left(x+2014\right)\left(\dfrac{1}{5}+\dfrac{1}{6}\right)\)
\(\left(x+2014\right)\dfrac{11}{14}=\left(x+2014\right)\dfrac{11}{30}\)
Dấu ''=''↔x=-2014
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4028 x 0,5 + 4028 + 2014 : \(\dfrac{1}{2}\) x 1,5 + 4028 : 0,5
= 4028 x 0,5 + 4028 x 1 + 2014 x 2 x 1,5 + 4028 x 2
= 4028 x 0,5 + 4028 x 1 + 4028 x 1,5 + 4028 x 2
= 4028 x ( 0,5 + 1 + 1,5 + 2)
= 4028 x 5
= 20140
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2014 x 3 + 4028 x 2 + 2014 x 5 - 2014 x 2
= 2014 x 3 + 2014 x 2 x 2 + 2014 x 5 - 2014 x 2
= 2014 x 3 + 2014 x 4 + 2014 x 5 - 2014 x 2
= 2014 x ( 3 + 4 + 5 - 2 )
= 2014 x 10 = 20140
\(2014\text{×}3+4028\text{×}2+2014\text{×}5-2014\text{×}2\\ =2014\text{×}3+2014\text{×}2\text{×}2+2014\text{×}5-2014\text{×}2\\ =2014\text{×}3+2014\text{×}4+2014\text{×}5-2014\text{×}2\\ =2014\text{×}\left(3+4+5-2\right)=2014\text{×}10=20140\)
\(\frac{x+2014}{2}+\frac{2x+4028}{7}=\frac{x+2014}{5}+\frac{x+2014}{6}\)
<=> \(\frac{x+2014}{2}+\frac{2\left(x+2014\right)}{7}=\frac{x+2014}{5}+\frac{x+2014}{6}\)
<=> \(\frac{x+2014}{2}+\frac{x+2014}{\frac{7}{2}}=\frac{x+2014}{5}+\frac{x+2014}{6}\)
<=> \(\frac{x+2014}{2}+\frac{x+2014}{\frac{7}{2}}-\frac{x+2014}{5}-\frac{x+2014}{6}=0\)
<=> \(\left(x+2014\right)\left(\frac{1}{2}+\frac{1}{\frac{7}{2}}-\frac{1}{5}-\frac{1}{6}\right)=0\)
Vì \(\frac{1}{2}+\frac{1}{\frac{7}{2}}-\frac{1}{5}-\frac{1}{6}\ne0\)
=> x + 2014 = 0 <=> x = -2014
Bài làm :
\(\frac{x+2014}{2}+\frac{2x+4028}{7}=\frac{x+2014}{5}+\frac{x+2014}{6}\)
\(\Rightarrow\frac{x+2014}{2}+\frac{2x+4028}{7}-\frac{x+2014}{5}-\frac{x+2014}{6}=0\)
\(\Rightarrow\frac{x+2014}{2}+\frac{2.\left(x+2014\right)}{7}-\frac{x+2014}{5}-\frac{x+2014}{6}=0\)
\(\Rightarrow\left(x+2014\right).\left(\frac{1}{2}+\frac{2}{7}-\frac{1}{5}-\frac{1}{6}\right)=0\)
\(\Rightarrow x+2014=0:\left(\frac{1}{2}+\frac{2}{7}-\frac{1}{5}-\frac{1}{6}\right)\)
\(\Rightarrow x+2014=0\)
\(\Rightarrow x=-2014\)
Vậy x = - 2014 .
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