tìm x X - 3 phần 2 = 11 phần 4
K
Khách
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B
31 tháng 8 2020
Bài làm :
1)\(\frac{3}{2}+\frac{5}{2}-\frac{4}{2}=\frac{3+5-4}{2}=\frac{4}{2}=2\)
2)\(\frac{2}{5}\times\frac{1}{2}\div\frac{1}{3}=\frac{2\times1\times3}{5\times2\times1}=\frac{6}{10}=\frac{3}{5}\)
3)\(\frac{2}{9}\div\frac{9}{2}\times\frac{1}{2}=\frac{2\times2\times1}{9\times9\times2}=\frac{4}{162}=\frac{2}{81}\)
4)\(\left(\frac{4}{11}+\frac{3}{11}\right)\times\frac{2}{6}=\frac{4+3}{11}\times\frac{2}{6}=\frac{7}{11}\times\frac{2}{6}=\frac{7\times2}{11\times6}=\frac{14}{66}=\frac{7}{33}\)
6 tháng 3 2017
\(\frac{1}{5.8}\)+\(\frac{1}{8.11}\)+\(\frac{1}{11.14}\)+........+\(\frac{1}{x.\left(x+3\right)}\)=\(\frac{101}{1540}\)
3(.\(\frac{1}{5.8}+\frac{1}{8.11}\)+\(\frac{1}{11.14}+.......+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}.3=\frac{303}{1540}\)
\(\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+.....+\frac{3}{x\left(x+3\right)}=\frac{303}{1540}\)
\(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+....+\frac{1}{x}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\frac{1}{x+3}=\frac{1}{5}-\frac{303}{1540}=\frac{1}{308}\)
=>\(x+3=308\)
\(x=308-3=305\)
Vậy \(x=305\)
S
6 tháng 3 2017
\(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x\left(x+3\right)}=\frac{101}{1540}\)
=> \(\frac{1}{3}\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}\right)=\frac{101}{1540}\)
=> \(\frac{1}{5}-\frac{1}{x+3}=\frac{101}{1540}:\frac{1}{3}\)
=> \(\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}\)
=> \(\frac{1}{x+3}=\frac{1}{5}-\frac{303}{1540}\)
=> \(\frac{1}{x+3}=\frac{1}{308}\)
=> x + 3 = 308
x = 308 - 5
x = 303
30 tháng 4 2017
\(\frac{3}{2}\)\(+\)\(\frac{5}{2}\)\(-\)\(\frac{4}{2}\)\(=\)\(\left(\frac{3}{2}+\frac{5}{2}\right)-\frac{4}{2}\)
\(=\frac{8}{2}-\frac{4}{2}=\frac{4}{2}=2\)
30 tháng 4 2017
\(\frac{2}{5}\)\(x\)\(\frac{1}{2}\)\(:\)\(\frac{1}{3}\)\(=\)\(\left(\frac{2}{5}x\frac{1}{2}\right)\)\(:\)\(\frac{1}{3}\)
\(=\)\(\frac{2}{10}\)\(:\)\(\frac{1}{3}\)\(=\frac{2}{10}x\frac{3}{1}\)\(=\frac{6}{10}=\frac{3}{5}\)
NK
1
21 tháng 2 2022
bài 4:so sánh
5/2 lớn hơn 3/7
4/3 lớn hơn,3/2 lớn hơn
bài 6:rút gọn các phân số sau:
3/9=1/3 9/12=3/4 8/18=4/9 60/36=10/6 17/34=1/2 17/51=1/3 35/100=7/20 25/100=1/4 8/1000=1/125 24/30=4/5 18/54=1/3 72/42=12/7
đay nhé mk chưa làm hết đc bn viết liền quá mk nhìn khó mà mk hỏi bài 7 là nhân hay cộng vậy?
S
16 tháng 4 2017
b, \(\frac{x+1}{2009}+\frac{x+2}{2009}=\frac{x+10}{2000}+\frac{x+11}{1999}\)
\(\Rightarrow\left(\frac{x+1}{2009}+1\right)+\left(\frac{x+2}{2008}+1\right)=\left(\frac{x+10}{2000}+1\right)+\left(\frac{x+11}{1999}+1\right)\)
\(\Rightarrow\frac{x+1+2009}{2009}+\frac{x+2+2008}{2008}=\frac{x+10+2000}{2000}+\frac{x+11+1999}{1999}\)
\(\Rightarrow\frac{x+2010}{2009}+\frac{x+2010}{2008}=\frac{x+2010}{2000}+\frac{x+2010}{1999}\)
\(\Rightarrow\frac{x+2010}{2009}+\frac{x+2010}{2008}-\frac{x+2010}{2000}-\frac{x+2010}{1999}=0\)
\(\Rightarrow\left(x+2010\right)\left(\frac{1}{2009}+\frac{1}{2008}-\frac{1}{2000}-\frac{1}{1999}\right)=0\)
Mà \(\frac{1}{2009}+\frac{1}{2008}-\frac{1}{2000}-\frac{1}{1999}\ne0\)
=> x + 2010 = 0 => x = -2010
27 tháng 8 2018
a) \(\left(8\frac{4}{5}x-50\right):0,4=5\)
\(\Rightarrow\left(\frac{44}{5}x-50\right)=5.0,4\)
\(\Rightarrow\frac{44}{5}x-50=2\)
\(\Rightarrow\frac{44}{5}x=2+50\)
\(\Rightarrow\frac{44}{5}x=52\)
\(\Rightarrow x=\frac{65}{11}\)
b) \(\left(\frac{5x}{3}-3\right):15=\frac{3}{10}\)
\(\Rightarrow\frac{5x}{3}-3=\frac{3}{10}.15\)
\(\Rightarrow\frac{5x}{3}-3=\frac{45}{10}\)
\(\Rightarrow\frac{5x}{3}=\frac{45}{10}+3\)
\(\Rightarrow\frac{5x}{3}=\frac{15}{2}\)
\(\Rightarrow5x.2=3.15\)
=> 5x.2 = 45
=> 5x = 45 : 2
=> 5x = 45/2
=> x = 9/2
\(x-\frac{3}{2}=\frac{11}{4}\)
\(x=\frac{11}{4}+\frac{3}{2}\)
\(x=\frac{17}{4}\)
\(x-\frac{3}{2}=\frac{11}{4}\)
\(x=\frac{11}{4}+\frac{3}{2}\)
\(x=\frac{11}{4}+\frac{6}{4}\)
\(x=\frac{17}{4}\)