![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(x+\frac{5}{3}\right)\cdot\frac{9}{13}=\frac{2}{3}\)
\(x+\frac{5}{3}=\frac{2}{3}:\frac{9}{13}\)
\(x+\frac{5}{13}=\frac{26}{27}\)
\(x=\frac{5}{13}-\frac{26}{27}\)
\(x=\frac{-203}{351}\)
b) \(43770:x=560-434\)
\(43770:x=126\)
\(x=43770:126\)
\(x=\frac{7295}{21}\)
c) \(x:3\frac{1}{3}=2\frac{2}{5}+\frac{7}{10}\)
\(x:\frac{10}{3}=\frac{12}{5}+\frac{7}{10}\)
\(x:\frac{10}{3}=\frac{31}{10}\)
\(x=\frac{31}{10}\cdot\frac{10}{3}\)
\(x=\frac{31}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1.a) (-23)+13+(-17)+75
=-10+(-17)+75
=-27+75
=48
b) (-123)+|-13|+(-7)
=(-123)+13+(-7)
=-110+(-7)
=-117
c) |-10|+|45|+(-|-455|)+|-750|
=10+45+(-455)+750
=55+(-455)+750
=-400+750
=350
2.a) |x-2|=0
Suy ra x-2=0
x =0-2
x=-2
Vay x=-2
b) x-5=7-(-3)
x-5=7+3
x-5=10
x =10+5
x =15
Vay x=15
c) |X|-5=3
|X| =3+5
|X| =8
Suy ra x=8;x=-8
Vay x=8;x=-8
tính toán như bình thường, cẩn thận lúc phá ngoặc và trị tuyệt đối của 1 số luôn là 1 số không âm là đc
![](https://rs.olm.vn/images/avt/0.png?1311)
240-[23+(13+24.3-x)]=132
240-[23+(13+168-x)]=132
240-[23+(181-x)]=132
|
x-8:4-(46-23.2+6.3)=0
\(x-8:4-\left(46-23.2+6.3\right)=0\)
\(x-2-\left(46-46+18\right)=0\)
\(x-2-18=0\)
\(x-2=0+18\)
\(x-2=18\)
\(x=18+2\)
\(x=20\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A, 2 . ( x - 3 ) + 1 = -25
2.(x-3)=-25-1
2.(x-3)=-26
x-3 =-26:2
x-3 =-13
x=-13+3
x=-10
B , | 3 . x + 1 | + 24 = 13
|3.x+1|=13-24
|3.x+1|=-11
TH1:
3.x+1=-11
3.x =-11-1
3.x =-12
x =-12:3
x =-4
TH2:
3.x+1=-(-11)
3.x+1=11
3.x =11-1
3x=10
x=10/3
vậy x=-4 ;10/3
a), 2 . ( x - 3 ) + 1 = -25
2.(x-3)=-25-1
2.(x-3)=-26
x-3 =-26:2
x-3 =-13
x=-13+3
x=-10
b)| 3 . x + 1 | + 24 = 13
|3.x+1|=13-24
|3.x+1|=-11
TH1:
3.x+1=-11
3.x =-11-1
3.x =-12
x =-12:3
x =-4
TH2:
3.x+1=-(-11)
3.x+1=11
3.x =11-1
3x=10
x=10/3
vậy x=-4 ;10/3
![](https://rs.olm.vn/images/avt/0.png?1311)
c)\(\Leftrightarrow\)(x+1)+2 chia hết x+1
\(\Rightarrow\)2 chia hết x+1
\(\Rightarrow\)x+1 ∈ {1,-1,2,-2}
\(\Rightarrow\)x ∈ {0,-2,1,-3}
c) \(x+3⋮x+1\)
\(\Rightarrow x+1+2⋮x+1\)
\(\Rightarrow2⋮x+1\) ( vì \(x+1⋮x+1\) )
\(\Rightarrow x+1\in\text{Ư}_{\left(2\right)}\)
\(\text{Ư}_{\left(2\right)}=\text{ }\left\{1;-1;2;-2\right\}\)
\(x+1\) | \(1\) | \(-1\) | \(2\) | \(-2\) |
\(x\) | \(0\) | \(-2\) | \(1\) | \(-3\) |
vậy................
10+(2x+1)2:3=13
=>(2x+1)2:3=13-10
=>(2x+1)2=3.3=32
=>2x+1=3
=>2x=3-1
=>x=2:2
=>x=1
vậy x=1
10+(2x+1)^2:3=13
(2x+1)^2:3=13-10
(2x+1)^2:3=3
(2x+1)^2=3:3
(2x+1)^2=1
(2x+1`)=1*2
(2x+1)=2
2x=2-1
x=1
x=1:2
x=0,5