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phamthiminhtrang
\(a,x=\frac{3}{6}-\frac{8}{16}\)
\(\Rightarrow x=0\)
\(b,\frac{12}{16}:x=\frac{32}{64}\)
\(x=\frac{12}{16}:\frac{32}{64}\)
\(x=\frac{12}{16}\cdot\frac{64}{32}\)
\(x=\frac{3}{8}\)
\(a,\)\(x\)\(=\frac{3}{6}-\frac{8}{16}=\frac{1}{2}-\frac{1}{2}=0\)
\(b,\)\(\frac{12}{16}\)\(:\)\(x\)\(=\frac{32}{64}\)
\(=>\) \(x\)\(=\)\(\frac{12}{16}:\frac{32}{64}\)
\(x\) \(=\)\(\frac{12}{16}.\frac{64}{32}\)
\(x\)\(=\)\(\frac{3}{4}.2\)
\(x\)\(=\)\(\frac{6}{4}=\frac{3}{2}\)
a) .12 = 0
x = 1.
Vậy x =1.
b) .32 = 32
x = 1
Vậy x = 1.
c) x.x = 16
Ta thấy 4.4 = 16 nên x = 4.
Vậy x =4.
d) .0 = 0
Ta thấy mọi số tự nhiên nhân với 0 đều bằng 0.
Do đó có vô số thỏa mãn điều kiện
Mà x là chữ số nên x ∈ {1; 2; 3; 4; 5; 6; 7; 8; 9}.
Hơn nữa x ≠ 0 nên x ∈ {1; 2; 3; 4; 5; 6; 7; 8; 9}.
Vậy x ∈ {1; 2; 3; 4; 5; 6; 7; 8; 9
\(a.\frac{27.45+27.55}{2+4+6+...+14+16+18}=\frac{27.100}{\frac{\left(2+18\right).9}{2}}=30\)
\(b.\frac{26.108-26.12}{32-28+24-20+16-12+8-4}=\frac{26\left(108-12\right)}{\left(32-28\right).4}=\frac{26.96}{4.4}=156\)
\(c.\frac{27.4500+135.550.2}{2+4+6+...+14+16+18}=\frac{270.450+270.550}{\frac{\left(2+8\right).9}{2}}\)
\(d.\frac{48.700-24.45.20}{45-40+35-30+25-20+15-10+5}=\frac{48.700-48.450}{5.5}\)\(=\frac{48\left(700-450\right)}{25}=\frac{48.250}{25}=480\)
#ĐinhBa
a: \(\Leftrightarrow x^3=\dfrac{539}{64}\)
hay \(x=\dfrac{7\sqrt{11}}{4}\)
c: \(\Leftrightarrow2^{2x-1}=2^9\cdot2^2=2^{11}\)
=>2x-1=11
hay x=6
d: \(\Leftrightarrow x^{17}-x=0\)
\(\Leftrightarrow x\left(x-1\right)\left(x+1\right)=0\)
hay \(x\in\left\{0;1;-1\right\}\)
â) (81+19)+ 243
= 100 + 243
= 343
b) 168+ 79+132
= (168+132)+79
= 300 +132
=432
c) 5.25.2.16.4
=(5.2).(25.4).16
= 10.100.16
= 1000.16
= 16000
d) 32.17+32.53
= 32.(47+53)
= 32.100
= 3200
\(a,4^{21}:16^5.\)
\(=4^{21}:\left(4^2\right)^5.\)
\(=4^{21}:4^{10}.\)
\(=4^{21-10}=4^{11}.\)
Vậy.....
\(b,32^8:4^{19}.\)
\(=\left(2^5\right)^8:\left(2^2\right)^{19}.\)
\(=2^{40}:2^{38}.\)
\(=2^{40-38}.\)
\(=2^2=4.\)
Vậy.....
\(c,27^{15}:9^{22}.\)
\(=\left(3^3\right)^{15}:\left(3^2\right)^{22}.\)
\(=3^{45}:3^{44}.\)
\(=3^{45-44}.\)
\(=3^1=3.\)
Vậy.....
\(d,25^{10}:125^6.\)
\(=\left(5^2\right)^{10}:\left(5^3\right)^6.\)
\(=5^{20}:5^{18}.\)
\(=5^{20-18}.\)
\(=5^2=25.\)
Vậy.....
~ Hok tốt!!! ~ :))
a, 421 : 165
= 421 : (42 )5
= 421 : 410
= 411
b, 328 : 419
= (25)8 : (22 )19
= 240 : 238
= 22
c, 2715 : 922
= (33 ) 15 : (32 )22
= 345 : 344
= 3
d, 2510 : 1256
= (52)10 : (53)6
= 520 : 518
= 52
a: \(=\dfrac{-4}{7}+\dfrac{7}{16}=\dfrac{-64+49}{112}=\dfrac{-15}{112}\)
b: \(=\dfrac{5}{16}\cdot32=10\)
c: \(=\dfrac{\left(-3\right)^2}{5^2}=\dfrac{9}{25}\)
d: \(=\dfrac{4}{5}\cdot\dfrac{-3+2}{10}=\dfrac{4}{5}\cdot\dfrac{-1}{10}=\dfrac{-4}{50}=\dfrac{-2}{25}\)
a) \(\frac{24-x}{16^5}=32^6\)
=> 24 - x = 326.165
<=> 24 - x = (25)6 . (24)5
<=> 24 - x = 230 . 220
<=> 24 - x = 250
<=> x = 24 - 250
b) (-2)x = -46.85
<=> (-2)x = -(22)6.(23)5
<=> (-2)x = -212.215
<=> (-2)x = -227
<=> (-2)x = (-2)27
<=> x = 27
Vậy x = 27
d) \(2^x=\frac{2^8}{4^4}\)
<=> \(2^x=\frac{2^8}{\left(2^2\right)^4}\)
<=> \(2^x=\frac{2^8}{2^8}\)
<=> 2x = 1 <=> x = 0
a.
\(\frac{24-x}{16^5}=32^6\)
( 24 - x ) : 165 = 326
24 - x = 326 . 165
24 - x = ( 16 )2.6 . 165
24 - x = 1612 . 165
24 - x = 1612 + 5
24 - x = 1617
x = 24 - 1617
Vậy x = 24 - 1617
b.
( - 2 )x = - 46 . 85
( - 2 )x = - 46 . ( - 4 ) - 2 . 5
( - 2 )x = - 46 . ( - 4 )- 10
( - 2 )x = - 4 6 + ( - 10 )
( - 2 )x = - 4-4
( - 2 )x = ( - 2 )-2 . ( - 4 )
( - 2 )x = ( - 2 )8
=> x = 8
Vậy x = 8
\(a,8^4\times16^5\times32=\left(2^3\right)^4\times\left(2^4\right)^5\times2^5=2^{3\times4}\times2^{4\times5}\times2^5=2^{12}\times2^{20}\times2^5=2^{12+20+5}=2^{37}\)
\(b,27^4\times81^{10}=\left(3^3\right)^4\times\left(3^4\right)^{10}=3^{3\times4}\times3^{4\times10}=3^{12}\times3^{40}=3^{12+40}=3^{52}\)
\(c,625^5\div25^7=\left(5^4\right)^5\div\left(5^2\right)^7=5^{20}\div5^{14}=5^{20-14}=5^6\)
Đáp án là C
Ta có 32 ⋮ 16; 112 ⋮ 16 ⇒ ƯCLN ( 16; 32; 112) = 16