Question

[Phuong Nguyen]

 

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(\dfrac{7}{2}-\dfrac{3}{2}+5=5+2=7\)

b: \(\dfrac{2}{7}+\dfrac{1}{5}+\dfrac{5}{7}+\dfrac{4}{5}\)

\(=\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{1}{5}+\dfrac{4}{5}\right)\)

=1+1=2

c: \(\dfrac{7}{9}\cdot\dfrac{5}{15}+\dfrac{7}{9}\cdot\dfrac{10}{15}\)

\(=\dfrac{7}{9}\left(\dfrac{5}{15}+\dfrac{10}{15}\right)\)

\(=\dfrac{7}{9}\cdot\dfrac{15}{15}=\dfrac{7}{9}\)

d: \(\dfrac{13}{19}+2025+\dfrac{6}{19}+2024\)

\(=\left(\dfrac{13}{19}+\dfrac{6}{19}\right)+\left(2025+2024\right)\)

=4049+1=4050

e: \(\dfrac{7}{30}+\dfrac{12}{37}+\dfrac{23}{30}+\dfrac{25}{37}\)

\(=\left(\dfrac{7}{30}+\dfrac{23}{30}\right)+\left(\dfrac{12}{37}+\dfrac{25}{37}\right)\)

\(=1+1=2\)

g: \(\dfrac{5}{7}\cdot\dfrac{5}{11}+\dfrac{5}{7}\cdot\dfrac{2}{11}+\dfrac{5}{7}\cdot\dfrac{4}{11}\)

\(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}+\dfrac{4}{11}\right)\)

\(=\dfrac{5}{7}\cdot\dfrac{11}{11}=\dfrac{5}{7}\)

e: \(\dfrac{20}{23}+5+\dfrac{3}{23}+5\)

\(=\left(\dfrac{20}{23}+\dfrac{3}{23}\right)+5+5\)

=1+10=11

f: \(\dfrac{4}{3}+\dfrac{11}{31}+\dfrac{2}{3}+\dfrac{20}{31}\)

\(=\left(\dfrac{4}{3}+\dfrac{2}{3}\right)+\left(\dfrac{11}{31}+\dfrac{20}{31}\right)\)

=2+1=3

h: \(\dfrac{5}{7}\cdot\dfrac{3}{13}+\dfrac{5}{7}\cdot\dfrac{10}{13}\)

\(=\dfrac{5}{7}\left(\dfrac{3}{13}+\dfrac{10}{13}\right)\)

\(=\dfrac{5}{7}\cdot\dfrac{13}{13}=\dfrac{5}{7}\)